[英]Grep exact match no dash
I have a list of genes like this one saved on a variable:我有一个这样的基因列表,保存在一个变量中:
NOL6
NPPC
NPRL2
NRG1
NT5C1B
NUDT19
OSER1
PAEP
PARD3
PCDHA4
I want to grep all these genes at another list:我想将 grep 所有这些基因放在另一个列表中:
chr3 NPRL2
chr5 NT5C1B
chr5 NT5C1B-RDH14
chr2 NUDT19
chr21 ABC
I tried this:我试过这个:
grep -w "^$genes$" list.txt
The problem is that it returns to me genes with a dash too:问题是它也用破折号返回给我的基因:
chr3 NPRL2
chr5 NT5C1B
chr5 NT5C1B-RDH14
chr2 NUDT19
I tried to use -x
but it doesn't work as the complete line doesn't match because of the first column.我尝试使用
-x
但它不起作用,因为第一列导致整行不匹配。
You will need to "anchor" the search patterns at the end of the lines and so:您需要在行尾“锚定”搜索模式,因此:
NOL6$
NPPC$
NPRL2$
etc.... ETC....
If you cannot amend the original file with the list of patterns, you can use sed and so with the patterns in file1 and the file to search as file:如果您无法使用模式列表修改原始文件,您可以使用 sed 等与 file1 中的模式和要搜索的文件作为文件:
grep -v -f <(sed 's/$/$/' file1) file
With sed, we are replacing the end of the line with $使用 sed,我们将行尾替换为 $
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