Python 2.7 fnmatch 不编辑文本

Question

I have a file with 600k+ records of string labels I am trying to edit with an update cursor using both the string modules and fnmatch to find patterns to edit. The section using fnmatch is successfully printing the matched records but not changing / parsing out the matched pattern.

There is no error and there is no change to the record. What am I missing with my syntax?

(Also - side issue, the last print row 4 statement only prints the first record of the file.)

The result samples are unchanged from original text 1000STR92SE 8000STR37NW 7000STR35SW 8000STR44 1000STR88SE 1000STR74SE

But results need to be 92SE 37NW 35SW 44 88SE 74SE

def newlabel():
#Global Conversions - works on editing the string
    with arcpy.da.UpdateCursor(mvum_fc, newfields) as uc:
        for row in uc:
            if row[1] == None or row[1].startswith('0'):
                row[4] = '{}'.format(row[4].lstrip(ascii_letters).replace('_', "-").lstrip('0').replace(' ', '-'))

            if row[1] == None or row[1].startswith('-'):
                row[4] = '{}'.format(row[4].lstrip('-').lstrip('0'))
#Regional Conversions - lstrip and replace tried - not changing text.
            elif row[1].startswith('0118'):
                pattern = ('?000STR*')
                match = fnmatch.fnmatch(row[4], pattern)
                if match == True:
                    row[4] = '{}'.format(row[4].lstrip('?000STR'))
                    print(row[4])
            uc.updateRow(row)
            print(row[4])

Answer 1

Remove the ? in the string you want to strip. It is a wildcard used in pattern matching.

row[4] = '{}'.format(row[4].lstrip('000STR'))

Answer 2

I have resolved this by avoiding the.lstrip:

row[4] = '{}'.format(row[4].lstrip('000STR'))

and simply replacing it with:

row[4] = '{}'.format(row[4][7:])