[英]Python index out of range exception
I've tried this:我试过这个:
x = []
for i in range(5)
x[i] = 0
print(x)
But it gives index out of range exception Why?但它给出了索引超出范围异常为什么?
Because there is not any value in list that's why In this case you have to use append因为列表中没有任何值,所以在这种情况下,您必须使用 append
like像
x = []
for i in range(5)
x.append(0) #x[i] = 0
print(x)
remove this line x[i] = 0
and put x.append(0)
删除此行
x[i] = 0
并放置x.append(0)
You're getting a index out of range exception
because there is nothing in your list.你得到一个
index out of range exception
,因为你的列表中没有任何内容。 If you want to loop 5 times and set x[i] = 0
there has to be a x[i]
first.如果你想循环 5 次并设置
x[i] = 0
必须先有一个x[i]
。
You created an empty list x = []
(not an array) and in a line x[i] = 0
where you are trying to assign element 0
with index=0
which does not exist at the time of initialization, here in your case it will be the first iteration of for
loop with i=0
.您创建了一个空列表
x = []
(不是数组),并在x[i] = 0
行中尝试分配index=0
的元素0
,这在初始化时不存在,这里是您的情况这将是for
循环的第一次迭代i=0
。
Here is the example:这是示例:
>>> x = []
>>> x[0] = 0
Traceback (most recent call last):
File "<pyshell#8>", line 1, in <module>
x[0] = 0
IndexError: list assignment index out of range
It will not allow you to assign element with index to an empty list.它不允许您将带有索引的元素分配给空列表。
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