下拉值和 php
[英]Drop down values and php
问题描述
I have a drop down menu/list in a html page.
我在 html 页面中有一个下拉菜单/列表。 These contain links as values and labels..这些包含作为值和标签的链接..
<form name="form1" method="post" action="">
<label>mylinks
<select name="select">
<option value="a.html">a</option>
<option value="b.html">b</option>
<option value="c.html">c</option>
</select>
</label>
I am trying to find a way how to get these links out of the form and in to the php page like $a = a $b = b and so on, so i can use it as an external link out of the drop down in a hidden page for checking my links if working or not.我正在尝试找到一种方法如何将这些链接从表单中取出并进入 php 页面，如 $a = a $b = b 等等，所以我可以将它用作下拉菜单中的外部链接一个隐藏页面，用于检查我的链接是否有效。 These links change from time to time..这些链接不时更改..
The form contains 3 values.该表单包含 3 个值。 a.html, b.html and c.html. a.html，b.html 和 c.ZFC35FDC70D5FC69D2698883AE22 if I have this page opened and can select one of three I go to a page.如果我打开此页面并且可以将 select 三个 I go 之一转到一个页面。 But I would like to have a place in this page that will echo the results of all 3 values out of the drop down as:但我想在这个页面中有一个位置，它将所有 3 个值的结果从下拉列表中回显为：
// This is not code. This is to show what I need
if value1 is <option value="a.html">a</option> then
echo '<a href=' .value1.'>a</a>';
so i could have result at the bottom
//This is the result
<a href="a.html">a</a>
<a href="b.html">b</a>
<a href="c.html">c</a>
My problem is how to extract the values from the form and echo them as href.我的问题是如何从表单中提取值并将它们作为 href 回显。 Is there a way with php or do I have to do a function or something else?有没有办法使用 php 还是我必须做 function 或其他什么？ Hope this helped.希望这有帮助。
3 个解决方案
解决方案1
0 2021-01-30 15:01:35
You can try this example, (it works as I understood to your question)你可以试试这个例子，（它就像我对你的问题的理解一样）
<!DOCTYPE html>
<html>
<head>
<title>Kostas Example</title>
</head>
<body>
<form name="form1" action="" method="post">
<label>My Links</label>
<select name="select">
<option value="a.html">Document a</option>
<option value="b.html">Document b</option>
<option value="c.html">Document c</option>
</select>
<button type="submit">Submit</button>
</form>
<?php
if(isset($_POST['select'])) {
$link = $_POST['select'];
echo "<a href='$link'>Document " . $link . "</a>";
}
?>
</body>
</html>
解决方案2
0 2021-01-30 17:00:02
This in not an answer.这不是答案。 Just were I am.只是我。 I entered the string of first html so it can be easier to work on...我输入了第一个 html 的字符串，这样可以更轻松地处理...
<?php
$html = '<form name="form1" method="post" action="">
<label>my_links
<select name="select">
<option value="a.html">a</option>
<option value="b.html">b</option>
<option value="c.html">c</option>
</select>
</label>';
echo $html;
$html2 = str_word_count($html, 1);
print_r($html2);
$count = 0;
foreach ($html2 as $value[$count]){
$count = $count + 1 ;
print $count."<br>";
//print "<br>";
$match_index = array_search("value", $value);
echo $match_index;
}
?>
解决方案3
0 2021-01-30 17:58:38
After a lot of search on the internet I came to an answer for this problem.在互联网上进行了大量搜索后，我找到了这个问题的答案。 This is the code这是代码
<?php
$html = '<form name="form1" method="post" action="">
<label>my_links
<select name="select">
<option value="a.html">a</option>
<option value="b.html">b</option>
<option value="c.html">c</option>
</select>
</label>';
echo $html;
echo "<br>";
$html2 = str_word_count($html, 1);
//print_r($html2);
$count = 0;
foreach ($html2 as $value){
$a[$count] = $html2;
//echo a[$count];
$match_index = array_search("value", $html2[$count]);
//echo $match_index;
$count = $count + 1 ;
//print $count."<br>";
}
//print "my result = ".$count."<br>";
foreach(range(0, $count) as $num){
if ("value" == $html2[$num]){
$a = $html2[$num +1];
$b = $html2[$num + 2];
echo '<a href="'.$a. '.'. $b .'">'. $a .'<br>';
}else{
echo "";
}
}
?>
There are a problem here.这里有一个问题。 If my link has two or more word separated with a space then I will not have in the end ".html" as I expect but ".second word".如果我的链接有两个或多个用空格分隔的单词，那么最后我将不会像我期望的那样有“.html”，而是“.second word”。 Not good.不好。 I am sure that code like this exist but I haven't found it yet.我确信存在这样的代码，但我还没有找到它。 If anyone has an idea please add a comment..如果有人有想法，请添加评论..
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