使用 ws 和特殊字符拆分 Javascript 字符串； 保持角色的机智

Question

I know there are tons of questions on this topic but I can't seem to produce a RegEx that works. I would like to split a string on whitespace AND a special character but keeping them intact.

I have the following string: "tobe " + '\x02' + " or nottob " and would like the output of the expression to produce the following: ["tobe", " ","\x02"," ","or"," ","notob"," "]

\x02 is a special block character and I'm using it as a placeholder.

EDIT I have tried "tobe " + '\x02' + " or not".sentence.split(/(\S+\s+)/); but end up with "tobe or nottob "

Thanks

Answer 1

You need to match each string and separate the groups
I created a formula that does exactly this. ([az\\0-9]+)|(\s+)
This matches every word that contains az 0-9 or \
Then it creates a new group and matches whitespace
It outputs an array of all of them. Including the whitespace

Also, if you match using /formula/gi, it will match G lobally and I nsensitive, so you can match az or AZ without the extra characters in the formula.

Edit: A shorter method, is to use the Not-Whitespace Selector (\S) which will select all characters EXCEPT whitespace. SO, you can use (\S+|\s+) which will select every nonspace set and every set of spaces. Its shorter, but you cant select which characters you want to save, itll just save everything that isnt a space, along with everything that IS a space.

The reason you cant match the \ is because its an escape character, and you need \. Ive included this in the live JS example aswell.

However, when using console.log, it doesnt need escaping

Live Javascript Example:

 let matchString = "tobe \\x02 or nottob "; let firstMatch = matchString.match(/[az\\0-9]+|\s+/gi); console.log(firstMatch); let secondMatch = matchString.match(/\S+|\s+/gi); console.log(secondMatch);

Answer 2

if you want to use regex:

var str = "tobe   " + '\x02' + " or nottob    ";

var out = str.split(/(\s+|\\x02)/);

console.log(out);

[EDIT]

 var str = "tobe " + '\x02' + " or nottob "; var out = str.split(/(\s+|\\x02)/); out = out.filter(Boolean); console.log(out);

( .filter(Boolean) to remove empty item)