该程序不打印它是平局。 我究竟做错了什么？

Question

The following program is not printing "It's a tie" when the computer's choice is the same as the player's choice.

import random

print("welcome to rock,paper, scissors and dynamite game!")

moves=["rock","paper","scissors","dynamite"]

for i in range(1,6):

    print("Round",i)

    user_play=input("player "+str(i)+" choice?").lower().strip(" ")

    play_moves=random.choice(moves)

    computer_play=input("computer choices:"+play_moves).lower().strip(" ")
    
    if user_play== computer_play:
        print("It's a tie!")

What am I doing wrong?

Answer 1

The computer's choice is stored in the play_moves variable so you should compare user_play with play_moves to check if it's a tie:

if user_play == play_moves:
    print("It's a tie!")

Answer 2

The program that you just wrote doesn't actually print the computer's random choice but instead it again prompts for user input one more time.

computer_play=input("computer choices:"+play_moves).lower().strip(" ")

Instead you might wanted to write it like this -

print("Computer Choices : " + play_moves)

And moreover, at the end of the program, it doesn't check equality of the random computer guess ( play_moves ) and the user input ( user_play ) but instead it checks the equality of the second user input ( computer_play ) with the first input.

if user_play== computer_play:

So, to compare the user input and the computer's random guess you would do this -

if user_play == play_moves:

Ask in the comments if you still have any doubts and I will improve my answer. Thanks:)