如何根据给定的模式从列表中提取一组特殊的字符串/单词？

Question

I have below list of name_space characters:

existing_list = ['ns:Insurance/ns:Policy/ns24:Product/ns24:dpname','ns:Insurance/ns:Policy/ns25:Event/ns25:evtname','ns:Insurance/ns:Policy/ns26:Account/ns26:actnum']

updated_list = ['ns:Insurance/ns:Policy/ns14:Product/ns14:dpname','ns:Insurance/ns:Policy/ns15:Event/ns15:evtname','ns:Insurance/ns:Policy/ns16:Account/ns16:actnum']

Now I have to verify the pattern of item from the existing_list if those have been changed in the 'updated_list'.

For example: The namspace:

ns:Insurance/ns:Policy/ns24:Product/ns24:dpname

from existing_list has been updated with

ns:Insurance/ns:Policy/ns14:Product/ns14:dpname

in the 'updated_list' - ie number changed from 24 to 14

I am looking for a way to extract the pattern of string without including the 'ns' value, in this case 'Insurance/Policy/Product/dpname' from the 'updated_list'.

Here the pattern 'Insurance/Policy/Product/dpname' is available in the 'updated_list'

if I search for the pattern without 'ns' from existing_list - ie, 'Insurance/Policy/Product/dpname'

# ie:
pattern_string = 'Insurance/Policy/Product/dpname'
for element in updated_list:
    result = re.match(pattern_string, element) 

it should return:

''ns:Insurance/ns:Policy/ns14:Product/ns14:dpname'' # from the 'updated_list'

because we are checking to get the updated ns value from the updated_list .

What is the right approach to get this?

Answer 1

@Cloud_Hari kindly try this solution,

import re
pattern = r"([\d]+)"
numbers = []
existing_list = ['ns:Insurance/ns:Policy/ns24:Product/ns24:dpname','ns:Insurance/ns:Policy/ns25:Event/ns25:evtname','ns:Insurance/ns:Policy/ns26:Account/ns26:actnum']
updated_list=['ns:Insurance/ns:Policy/ns14:Product/ns14:dpname','ns:Insurance/ns:Policy/ns15:Event/ns15:evtname','ns:Insurance/ns:Policy/ns16:Account/ns16:actnum']

for previous, current in zip(existing_list, updated_list):
    if re.findall(pattern, previous)[0] != re.findall(pattern, current)[0]:
        print("previous list value => ", previous)
        print("Has been updated to => ", current)
        #Feel free to add your logic here

This uses REGEX to match the occurrences of the number in the previous list and compare it with the second list, and if they are different they will print them out, and you can add your logic inside the if block.

The REGEX pattern => ([\d+]) forms a group of matching decimals.