[英]How to order by substring in python SQLAlchemy
I'm using SQLAlchemy for my python script, and I am unable to order the select query in asc order based on a substring column value.我将 SQLAlchemy 用于我的 python 脚本,并且我无法根据 ZE83AED2DBBDF00BEC67 列值 select 以升序顺序订购 select 查询。
The actual query is this one实际查询是这个
books = Book.order_by(Book.id.asc(), Book.title.asc()).all()
but I want to order by a substring of the first 4 digits of the title
column.但我想按
title
列前 4 位数字的 substring 订购。
In SQL language I would do so在 SQL 语言中我会这样做
SELECT *
FROM book
ORDER BY id asc, substring(title,0,5) asc;
but in SQLAlchemy?但在 SQLAlchemy 中?
tnx tnx
You can use the function substr:您可以使用 function 子字符串:
from sqlachemy import func
books = Book.order_by(Book.id.asc(), func.substr(Book.title, 1, 4).asc()).all()
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