[英]send post json with php (curl)
i done search tutorial for send post json with curl.. but for this value i cant find in here.. and my question how to convert to array post json in value if like this, and this my value post json i done search tutorial for send post json with curl.. but for this value i cant find in here.. and my question how to convert to array post json in value if like this, and this my value post json
{
"payment_type": "bca_klikpay",
"transaction_details": {
"order_id": "orderid-01",
"gross_amount": 11000
},
"item_details": [
{
"id": "1",
"price": 11000,
"quantity": 1,
"name": "Mobil "
}
],
"customer_details":{
"first_name": "John",
"last_name": "Baker",
"email": "john.baker@email.com",
"phone": "08123456789"
},
"bca_klikpay": {
"description": "Pembelian Barang"
}
}
i done try to php array like this but still error我尝试过像这样的 php 数组,但仍然错误
$item = array('id' => 'id1', 'price' => 11000, 'quantity' => 1 , 'name' => 'Mobil');
$data2 =array('payment_type' => 'bca_klikpay',
'transaction_details' => array('order_id' => 'orderid-01', 'gross_amount' => 11000),
'item_details' => array([$item]),
'customer_details'=> array('first_name' => 'john',
'last_name' => 'baker', 'email' => 'john.baker@email.com', 'phone' => 08123456789),
'bca_klikpay' => array('description' => 'Pembelian Barang'));
maybe someone can help me.. and sory for my bad english也许有人可以帮助我.. 对不起我的英语不好
thanks谢谢
There is the following error - the phone number has to be string, not number, so it would look like this 'phone' => '08123456789'
, because numbers cannot begin with 0.有以下错误 - 电话号码必须是字符串,而不是数字,所以它看起来像这样
'phone' => '08123456789'
,因为数字不能以 0 开头。
Beside this, there is the following issue - You should not set item_details like this, but rather 'item_details' => [$item]
.除此之外,还有以下问题 - 您不应该像这样设置 item_details,而应该设置
'item_details' => [$item]
。 You do not need 2 nested arrays, just one.您不需要 2 个嵌套的 arrays,只需一个。 (
array()
is equal to []
. They are practically the same in your use case. So you are doing something like array(array($item))
, which is wrong) (
array()
等于[]
。它们在您的用例中实际上是相同的。所以您正在做类似array(array($item))
的事情,这是错误的)
What else, you have to do a $json = json_encode($data2);
还有什么,你必须做一个
$json = json_encode($data2);
at the end and it will return what you want it to.最后,它会返回你想要的。
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