Matplotlib 固定子图 plot 高度
[英]Matplotlib Fixed subplot plot height
问题描述
I am trying to plot a series of character that have been segmented, each character has the same height but a relative width dependant on if the segmentation was successful.
我正在尝试 plot 一系列已分割的字符，每个字符具有相同的高度但相对宽度取决于分割是否成功。 However, this changing width is affecting the height of the subplot.但是，这种变化的宽度正在影响子图的高度。 Is there a way to make each of these subplots the same shape?有没有办法使这些子图中的每一个都具有相同的形状？ I have tried each of the following:我已经尝试了以下各项：
plt.axis('equal')
plt.axis('scaled')
width_ratios=[3, 1], height_ratios=[4, 1]
gridspec_kw={'width_ratios': [3, 1]}
fig, ax = plt.subplots(1, len(i))
for x in range (0, len(i)):
ax[x].imshow(i[x])
plt.savefig("img")
Thanks in advance提前致谢
EDIT 1: Suggested by @Jody Klymak编辑 1：@Jody Klymak 建议
ax[x].set_xlim([0, 40])
ax[x].set_ylim([0, 50])
EDIT 2: Suggested by @a11 I implemented your suggestion and it appears to have no effect.编辑 2：@a11 建议我实施了您的建议，但似乎没有效果。
fig, ax = plt.subplots(1, len(i), sharey=True, figsize=(10,10))
for x in range (0, len(i)):
ax[x].imshow(i[x])
ax[x].set_aspect(aspect='equal')
EDIT 3:编辑 3：
i values:我的价值观：
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dtype=uint8)]
4 个解决方案
解决方案1
0 2021-02-01 17:23:02
I would just give them the same limits:我会给他们同样的限制：
import matplotlib.pyplot as plt
import numpy as np
fig, axs = plt.subplots(1, 2)
axs[0].imshow(np.ones((15, 3)))
axs[1].imshow(np.ones((3, 15)))
for ax in axs:
ax.set_xlim([0, 15])
ax.set_ylim([0, 15])
plt.show()
解决方案2
0 2021-02-01 17:56:28
Another approach is to put all the images in one big axes:另一种方法是将所有图像放在一个大轴上：
import matplotlib.pyplot as plt
import numpy as np
data = [np.ones((15, 3)), np.ones((3, 15))]
fig, ax = plt.subplots()
rh = 0
for A in data:
M, N = A.shape
ax.imshow(A, extent=(rh, rh + N, 0, M))
rh += 1 + N
ax.set_xlim(0, rh)
ax.set_ylim(0, 15)
plt.show()
You can probably figure out how to change extent if you would like the baseline shifted somehow.如果您希望基线以某种方式移动，您可能会弄清楚如何更改extent 。
解决方案3
0 已采纳 2021-02-01 20:59:00
This talks about using aspect="auto" so I did: 这谈到了使用 aspect="auto" 所以我做了：
imshow(i[x], aspect="auto")
for each of the subplots which makes all the subplots the same size as the largest one.对于每个子图，使所有子图的大小与最大的子图相同。 This has the desired outcome, however, it does become slightly unreadable.这具有预期的结果，但是，它确实变得有点不可读。
for x in range (0, len(i)):
ax[x].imshow(i[x], aspect="auto")
So instead I made a function to calculate an aspect ratio for turning each image into the smallest size.因此，我制作了一个 function 来计算将每个图像转换为最小尺寸的纵横比。
def getAspectRatio(i):
shapes = []
#Get the width of each image
for x in range(0, len(i)):
shapes.append(i[x].shape[1])
#Find the max width
m = max(shapes)
ratios = []
#Add each ratio to the list
for x in range(0, len(i)):
ratios.append(i[x].shape[1] / m)
return ratios
ar = getAspectRatio(i)
for x in range (0, len(i)):
ax[x].imshow(i[x], aspect=ar[x])
解决方案4
0 2021-02-01 21:07:37
I might be misunderstanding something, but will something this simple work?我可能会误解一些东西，但是这么简单的东西会起作用吗？ The subplots are defined or built such that the y-axis limits are shared and the same in all subplots.子图的定义或构建使得 y 轴限制在所有子图中共享且相同。 The figure size is also defined when building the subplots, so you can control the dimensions of the final "page."在构建子图时也定义了图形大小，因此您可以控制最终“页面”的尺寸。 Then in the loop, each subplot is set to equal aspect, so that should make the letters legible.然后在循环中，每个子图都设置为相等的方面，这样应该使字母清晰。
fig, axes = plt.subplots(1, 6, figsize=(10,10), sharey=True)
for ii, ax in enumerate(axes.flat):
axes[ii].imshow(np.random.random((20,10)))
ax.set_aspect(aspect='equal')
Updated with more info from OP: A quick but perhaps unsatisfying solution is just to specify the figure size in a way that is a proxy for aspect ratio.更新了来自 OP 的更多信息：一个快速但可能不令人满意的解决方案就是以一种代表纵横比的方式指定图形大小。 Here, I use a figure that is twice as long as tall.在这里，我使用了一个身长两倍的人物。
fig, axes = plt.subplots(1, len(i), figsize=(10,5), sharey=True)
for nn, ax in enumerate(axes.flat):
axes[nn].imshow(i[nn])
ax.set_aspect(aspect='auto')
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