[英]How to convert number in start except last 4 digits in react native
In below response I am getting "43445567665" this value when I am mapping biomatricData.ninId:在下面的响应中,当我映射 biomatricData.ninId 时,我得到“43445567665”这个值:
biomatricData.ninId = 43445567665
Now I have to display only last 4 digit and rest should come like *
现在我只需要显示最后 4 位数字,rest 应该像
*
I have to change 43445567665
in below format我必须以以下格式更改
43445567665
Like - *******7665
喜欢 -
*******7665
<View style={{ flexDirection: 'row', marginBottom: 10 }}>
<RegularText text={'Nin Number : '} textColor='grey' style={{ marginBottom: 5 }} />
<Text>{biomatricData.ninId}</Text>
</View>
Put that biomatricData.ninId
in variable then complete action given below and just use that variable for show.将该
biomatricData.ninId
放入变量中,然后完成下面给出的操作,并使用该变量进行显示。
use following regex.使用以下正则表达式。
var str = "43445567665"; var replaced = str.replace(/.(?=.{4,}$)/g, '*'); console.log(replaced);
Try this code试试这个代码
var numToBeConverted = 327364829364;
String(numToBeConverted).split("").reverse().map((e, i) => i >= 4 ? "*" : e).reverse().join("");
You can make it a function if you want如果你愿意,你可以把它变成 function
function convertToBiometric(num) {
return String(num).split("").reverse().map((e, i) => i >= 4 ? "*" : e).reverse().join("");
}
Can be achieved using Array
methods like this.可以使用这样的
Array
方法来实现。
let numToBeConverted = '43445567665';
function covert(num){
let arr = Object.values(num);
return arr.splice(0, arr.length-4).fill('*').join('')
+ arr.splice(-4).join('');
}
console.log(covert(numToBeConverted));
//output - "*******7665"
We can use String padding to add the * sign in our string values to convert our string in sensitive data我们可以使用字符串填充在我们的字符串值中添加 * 符号以将我们的字符串转换为敏感数据
checkout the doc to apply string padding签出文档以应用字符串填充
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/padStart https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/padStart
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