如何将列中的结果拆分为 python 中的两个单独列？

Question

this the col that I need to split in python

I've tried this but it back with an error

events["top_element_info"]= events["top_element_info"].str.split(",", n = 1, expand = True)

error

Answer 1

Assuming you want the ids as your first column and points as the second one, you can do the following:

df = pd.DataFrame({"top_element_info": [{'id': 123, 'points': 20}, {'id': 124, 'points': 30}, {'id': 125, 'points': 40}]})
for col in ['id', 'points']:
    df[col] = [x[col] for x in df['top_element_info']]

Answer 2

I am assuming you want to split the string into two and store it into two columns. The issue is you are trying to split the string into two columns by assigning expand to True but trying to store it into a single column.

Try:

events["top_element_info_id"], events["top_element_info_points"] = events["top_element_info"].str.split(",", n = 1, expand = True)

Answer 3

after combining the solutions I've reached this

events["top_element_info"] = events["top_element_info"].apply(str)
events["top_element_info"].replace(regex=True,inplace=True,to_replace=r"'id':",value=r'')
events["top_element_info"].replace(regex=True,inplace=True,to_replace=r"'points': ",value=r'')
events["top_element_info"].replace(regex=True,inplace=True,to_replace=r"}",value=r'')
events["top_element_info"].replace(regex=True,inplace=True,to_replace=r"}",value=r'')

events[['top_element_info_id', 'top_element_info_points']] = events['top_element_info'].str.split(',', 2, expand=True)
events.head()

and it solved now thanks for all:)