在 Python 中将字符串转换为 integer 和反之亦然

Question

I have a string for example

>>> sample = "Hello World!"

What I want to make a function which can convert sample to int. I know about chr() and ord() . I've used this so far:

For String to Int

>>> res="".join([str(ord(char)) for char in sample])
>>> print(res)
72101108108111328711111410810033

Now the problem arise. How can I convert res back to sample . Any suggestion would be appreciated.

Note: sample string can also have unicode characters in it

Edit:

nchars=len(sample)
res = sum(ord(sample[byte])<<8*(nchars-byte-1) for byte in range(nchars)) # string to int
print(''.join(chr((res>>8*(nchars-byte-1))&0xFF) for byte in range(nchars))) #int to string

I found this solution but this is very slow do someone know to improve this

Answer 1

I am saving the num seperated by " " so it is possible to go back through convert it easier

This works and is simple:

i = "Hello World"
num = ""
for char in i:
    num += str(ord(char))+" "

print(''.join(num.split()))

back = ""
for n in num.split():
    back += chr(int(n))

print(back)

output:

721011081081113287111114108100
Hello World

Answer 2

sample = "Hello World!"
d1={k:str(ord(v)) for k,v in list(enumerate(sample))}
''.join(d1.values())
'72101108108111328711111410810033'
res1="".join([chr(int(char)) for char in d1.values()])
res1
'Hello World!'

In order to avoid the problem of which ord(chr) belongs to which chr? we need a mapping like data structure and dict is the best to store the each string and assign them to unique key using enumerate which will generate the keys on fly.

Our d1 looks like this:

{0: '72',
 1: '101',
 2: '108',
 3: '108',
 4: '111',
 5: '32',
 6: '87',
 7: '111',
 8: '114',
 9: '108',
 10: '100',
 11: '33'}

then comes the easy part converting the string values to int and applying chr on it to convert back into string.

Since OP donot want to use multiple variables or data structures.

sample = "Hello World!"
l_n=[str(ord(i))+str(ord('@')) for i in list(sample)]
text="".join(l_n)
n_l=[chr(int(i)) for i in text.split('64') if i.isnumeric()]
''.join(n_l)

The problem is we need to know where to apply char so I've added an extra @ to each letter so that it would be easy to convert it back