Python 字典聚合值列表

Question

Here is an example input:

[{'name':'susan', 'wins': 1, 'team': 'team1'}
{'name':'jack', 'wins':1, 'team':'team2'}
{'name':'susan', 'wins':1, 'team':'team1'}]

Desired output

[{'name':'susan', 'wins':2, 'team': 'team1'}
{'name':'jack', 'wins':1, 'team':'team2'}]

I have lots of the dictionaries and want to only add, the 'win' value, based on the 'name' value, and keep the 'team' values

I've tried to use Counter , but the result was

{'name':'all the names added toghther',
 'wins': 'all the wins added toghther'
}

I was able to use defaultdict which seemed to work

result = defaultdict(int)

for d in data:
  result[d['name']] += d['wins'])

but the results was something like

{'susan': 2, 'jack':1}

Here it added the values correctly but didn't keep the 'team' key

I guess I'm confused about defaultdict and how it works.

any help very appreciated.

Answer 1

Did you consider using pandas?

import pandas as pd


dicts = [
    {'name':'susan', 'wins': 1, 'team': 'team1'},
    {'name':'jack', 'wins':1, 'team':'team2'},
    {'name':'susan', 'wins':1, 'team':'team1'},
]
agg_by = ["name", "team"]

df = pd.DataFrame(dicts)
df = df.groupby(agg_by)["wins"].apply(sum)

df = df.reset_index()
aggregated_dict = df.to_dict("records")