如何过滤数组以仅在 Google Apps 脚本/Javascript 中完全匹配

Question

I'm trying to use Google Apps Script to filter only exact matches. I've seen similar questions, but I can't seem to apply them to my situation.

On one sheet, I have a table of information which has the item name in column A, its' ingredient in column B, and its' quantity in column C. Column A contains items named Test and Test 2. When I filter for Test 2, I get results of both Test and Test 2. Here is the code I'm using:

var costSheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('Cost');
var ingSheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('Recipe Ingredient');

// Create list of items to filter from the full list
var rows = costSheet.getLastRow();
var itemList = costSheet.getRange(2, 1, rows - 1).getValues();

// Convert itemList to array to be used in filter
itemList = itemList.join();

// Get full non-filtered data
var fullList = ingSheet.getRange('A2:C514').getValues();

// Apply filter criteria
function checkMatch(item) {
  return itemList.indexOf(item[0]) != -1;
}
filterList = fullList.filter(checkMatch);

// Clear target location, then place filtered data
costSheet.getRange('C2:E514').clearContent();
costSheet.getRange(2, 3, filterList.length, 3).setValues(filterList);

I don't have any trouble getting accurate results for multiple items from all three columns, and the only issue I have is when I try to filter an item that begins with the name of another item in the full list (eg filtering for Test 2 returns both Test and Test 2, when I want it to just return Test 2).

I am new to working with Google Apps Script/Javascript, hence the 'amateur' coding.

Answer 1

Explanation:

You are very close!

The issue is related to this line:

itemList = itemList.join();

Assuming that itemList = [["Test 2"],["Test 3"]] as a result of the getValues() method.

If you apply join you are converting the above array into the following string :

Test 1,Test 2

Therefore itemList.indexOf("Test") will return 0 which means your filter function will evaluate to true , but you don't want that since Test is not part of your array. You are mistakenly using the indexOf method of strings instead of the indexOf method of arrays .

Having said that, your goal is to use the the indexOf method of arrays . In order to do so, itemList needs to be an array and not a string.

To convert a 2D array [["Test 2"],["Test 3"]] into a 1D array [Test 1, Test 2] you can use flat .

Solution:

Change:

itemList = itemList.join();

To:

itemList = itemList.flat();

Improved Solution:

Going for the extra mile, you can shorten your code and make it more JavaScript modern like that:

function shorterFunction(){
  const ss = SpreadsheetApp.getActiveSpreadsheet();
  const costSheet = ss.getSheetByName('Cost');
  const ingSheet = ss.getSheetByName('Recipe Ingredient');
  const itemList = costSheet.getRange(2, 1, costSheet.getLastRow() - 1).getValues().flat();
  const fullList = ingSheet.getRange('A2:C514').getValues();
  const filterList = fullList.filter(r=>itemList.includes(r[0]))
  costSheet.getRange('C2:E514').clearContent();
  costSheet.getRange(2, 3, filterList.length, 3).setValues(filterList);
}

In this solution, I used an arrow function and includes .