对于语句增量并跳过代码的 rest

Question

I have the following code:

for a in range(0,len(customer_name),1):

     url = "https://whatever_my_url_is.com/" + customer_name[a] + "/"
     
     try:
               page = urllib.request.urlopen(url)
     except:
               print("Cannot load page, bad URL.")
               a = a + 1

    rest of my code

What it currently does:

• Goes through each customer, one at a time, and loads their page.
• If the URL is bad, I get the "Cannot load page, bad URL." message.
• The rest of my code continues like normal.

What I want it to do is immediately stop what it's doing and move to the next customer_name on the list, not continue the rest of the code.

Answer 1

You can use continue

for a in range(0,len(customer_name),1):

     url = "https://whatever_my_url_is.com/" + customer_name[a] + "/"
     
     try:
               page = urllib.request.urlopen(url)
     except:
               print("Cannot load page, bad URL.")
               continue

    rest of my code

Answer 2

An else clause may be used within a try statement, see Python doc :

try1_stmt ::=  "try" ":" suite
               ("except" [expression] ":" suite)+
               ["else" ":" suite]

Therefore you can also write your code as follows:

for a in customer_name:
     url = 'https://whatever_my_url_is.com/{}/'.format(a)
     try:
               page = urllib.request.urlopen(url)
     except:
               print("Cannot load page, bad URL.")
     else:
        rest of my Code

Other improvements:

1. range(start, stop, step) may be written as range(stop) if start is 0 and step is 1.

2. You may use a sequence item directly. instead of

   for index in range(len(sequence)): print(sequence[index])

   you should use:

    for item in iterable: print(item)