Django REST 框架 API：如何在 ZEF6784A1DA0D4D7 服务器上使用用户提供的名称（例如 username.jpg）保存/上传图像

Question

I want to upload image with the name (which is given by user) at Django server through rest API,but i am not be able to find out the solution for this.Please tell me how to upload image with given name. here is my code(mainly):

IN API TASK ->URLS:

from django.conf.urls import include, url
from django.contrib import admin
from rest_framework import routers
from django.conf import settings
from myapi import views

from django.conf.urls.static import static
#Define API Routes

router = routers.DefaultRouter()
router.register(r'myimage', views.myimageViewSet)  #we have only on viewset


urlpatterns = [
   url(r'^',include(router.urls)),
   url(r'^admin/',admin.site.urls),
]+static(settings.MEDIA_URL,document_root=settings.MEDIA_ROOT)

IN My API

1. MODEL

from django.db import models

# Create your models here.
class myimage(models.Model):
    my_name=models.CharField(max_length=50)
    my_image=models.ImageField(upload_to='Images/',default='Images/None/No-img.jpg')

    def __str__(self):
        return self.my_name

2.SERIALIZERS

from rest_framework import serializers
from .models import myimage

class myimageserializer(serializers.ModelSerializer):
    class Meta:
        model =myimage
       fields=('id','my_name','my_image')

3. VIEWS

from django.shortcuts import render
from .models import myimage
from rest_framework import viewsets
from .serializers import myimageserializer
from rest_framework import filters
import django_filters.rest_framework

class myimageViewSet(viewsets.ModelViewSet):
    queryset = myimage.objects.all()  #We use Filters for Ordering so remove order_by part
    serializer_class = myimageserializer
    filter_backends = (django_filters.rest_framework.DjangoFilterBackend,filters.OrderingFilter,)
    ordering  = ('id','my_name',)

4.ADMIN

from django.contrib import admin
from .models import myimage

admin.site.register(myimage)

Answer 1

You need to use FileParser to be able to get your image details in the request data object. I recommend you to follow the example in DRF's FileParser Example

Answer 2

I changed my code as mentioned below and now its working for me if you have any better solution please suggest here #happycoding

1. views.py

from django.shortcuts import render
from .models import myimage
from rest_framework import views
from .serializers import myimageserializer
import django_filters.rest_framework
from rest_framework.views import APIView
from rest_framework.response import Response
from rest_framework import status

class myimageView(APIView):
   
    def get(self, request):
        myimagelocal= myimage.objects.all()
        serializer = myimageserializer(myimagelocal, many=True)
        return Response(serializer.data)
  
    def post(self, request):
        myname=request.data['my_image'].name
        myformat=""
        for c in reversed(myname):
            myformat+=c
            if c=='.' :
                break
        myformat=myformat[: : -1]
        request.FILES['my_image'].name=request.data['my_name']+myformat
       
        serializer = myimageserializer(data=request.data)
        if serializer.is_valid():
            serializer.save()
            return Response(serializer.data, status=status.HTTP_201_CREATED)
        return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)
 

IN API_TASK->URLS:

from django.conf import settings
from django.conf.urls.static import static
from django.contrib import admin
from django.urls import path, include

urlpatterns = [
    path('admin/', admin.site.urls,name='admin'),
    path('',include('myapi.urls'))
]+static(settings.MEDIA_URL,document_root=settings.MEDIA_ROOT)

IN API_Task->myapi->url

from django.urls import path
from .views import myimagedetailsView, myimageView

urlpatterns = [
    path('myimage/', myimageView.as_view(),name='myimageView'),
]

Rest files unchanged