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与空表的左连接使在 php 中的 null 上连接的列,但在 phpmyadmin 中正常工作

[英]Left join with empty table makes the column that is joined on null in php, but works normally in phpmyadmin

I have a users and a userfollowers table.我有一个users和一个用户userfollowers表。 They both have a user_id column.他们都有一个user_id列。

The userfollowers table might be empty or does not have a match yet for a user in the users table, hence why i use a left join . userfollowers表可能是空的,或者还没有users表中的用户匹配,因此我使用left join

This is my query:这是我的查询:

SELECT * 
FROM users 
LEFT JOIN userfollowers ON users.user_id = userfollowers.user_id 
WHERE user_name = ?"

When I try to execute this query in my php prepared statement, it returns all columns correctly, except the user_id from the users table is suddenly NULL.当我尝试在我的 php 准备语句中执行此查询时,它会正确返回所有列,除了users表中的user_id突然变为 NULL。

When I try this query in phpmyadmin, it returns all columns including the user_id from the users table as intended.当我在 phpmyadmin 中尝试此查询时,它会按预期从users表中返回包括user_id在内的所有列。

Can someone tell me what is going on?有人可以告诉我发生了什么吗?

In PHP only 1 indice can exist in an array so the latter column, userfollowers.user_id overwrites the first value users.user_id .在 PHP 中,数组中只能存在 1 个索引,因此后一列userfollowers.user_id覆盖第一个值users.user_id You need to list the columns, use aliases for all columns, or use numeric indices (which will be difficult to determine which value is which).您需要列出列,为所有列使用别名,或使用数字索引(这将很难确定哪个值是哪个)。

You could do something like this if all columns from users should be returned:如果应返回users的所有列,您可以执行以下操作:

SELECT u.*, uf.somecolumn
FROM users as u
LEFT JOIN userfollowers as uf using(user_id) 
WHERE user_name = ?

The as u is a table alias, that allows you to use the shorter syntax when referencing the table. as u是表别名,允许您在引用表时使用较短的语法。 Tha same can be done for columns.对列也可以这样做。 With original query if you needed both user_id s could do:如果您需要两个user_id ,则使用原始查询可以执行以下操作:

SELECT u.user_id as users_id, uf.user_id as userfollowers_userid 
FROM users as u
LEFT JOIN userfollowers as uf using(user_id)
WHERE user_name = ?

then PHP would have both $row['userfollowers_userid'] and $row['users_id'] available.那么 PHP 将有$row['userfollowers_userid']$row['users_id']可用。

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