[英]Trying to add object onto text file
I am trying to upload a bunch of objects onto a text file in an organized manner but I keep on getting an error.我正在尝试以有组织的方式将一堆对象上传到文本文件中,但我不断收到错误消息。 I am not sure about objects and how to arrange them so they appear in the text document.我不确定对象以及如何排列它们以便它们出现在文本文档中。
class Customer:
def __init__(self, name, date, address, hkid, acc):
self.name = name
self.date = date
self.address = address
self.hkid = hkid
self.acc = acc
customer1 = Customer ("Sarah Parker","1/1/2000","Hong Kong, Tai Koo,Tai Koo Shing Block 22,Floor 10, Flat 1", "X1343434","2222")
customer2 = Customer ("Joe Momo","7/11/2002","Hong Kong, Tai Koo, Tai Koo Shing, Block 22, Floor 10, Flat 5", "C2327934","1234")
customer3 = Customer ("Brent Gamez","7/20/2002","Hong Kong, Tung Chung, Yun Tung, Block 33, Floor 10, Flat 9", "C1357434","2234")
customer4 = Customer ("Jose Gamez","7/20/2002","Hong Kong, Tung Chung, Yun Tung, Block 33, Floor 10, Flat 9", "C1357434","2234")
customer5 =Customer ("Viraj Ghuman","7/20/2002","Hong Kong, Heng Fa Chuen, 100 Shing Tai Road, Block 22, Floor 20, Flat 1", "C6969689","100000")
allCustom = [customer1, customer2, customer3, customer4, customer5]
def UpdateFile ():
global allCustom
OutFile = open("CustomInfo.txt","w")
for i in range (len(allCustom)):
for c in range (i):
OutFile.write(allCustom[i["\n","Name:",c.name,"\n"]])
OutFile.write(allCustom[i["Birth Date:",c.date,"\n"]])
OutFile.write(allCustom[i["Address:",c.address,"\n"]])
OutFile.write(allCustom[i["HKID:",c.hkid,"\n"]])
OutFile.write(allCustom[i["Account value:", c.acc,"\n"]])
OutFile.close()
You don't need two loops to get each object info.您不需要两个循环来获取每个 object 信息。 Maybe this is what you are looking for.也许这就是你要找的。
def UpdateFile():
global allCustom
Outfile = open("CustomInfo.txt", "w")
for i in allCustom:
Outfile.write(f'\nName: {i.name}\n')
...
Outfile.close()
i
and c
are integer list indexes. i
和c
是 integer 列表索引。 You can't use c.name
because it's not a Customer
object.您不能使用c.name
,因为它不是Customer
object。 And you can't index i[...]
because it's not a container.而且你不能索引i[...]
因为它不是一个容器。
You don't need nested loops, just one loop over all the customers.您不需要嵌套循环,只需对所有客户进行一个循环。 Your loop iterates i
from 0
to 4
.您的循环将i
从0
迭代到4
。 On the first iteration it iterates 0 times, on the second iteration it processes c == 0
, on the third iteration it processes c == 0
and c == 1
, and so on.在第一次迭代中,它迭代 0 次,在第二次迭代中,它处理c == 0
,在第三次迭代中,它处理c == 0
和c == 1
等
Then you can use a formatting operator to put the attributes into the strings that you're writing to the file (I've used f-strings below, but you can also use the %
operator or the .format()
method).然后,您可以使用格式化运算符将属性放入要写入文件的字符串中(我在下面使用了 f 字符串,但您也可以使用%
运算符或.format()
方法)。
def updateFile():
global allCustom;
with open("CustomInfo.txt", "w") as OutFile:
for c in allCustom:
OutFile.write(f"\nName:{c.name}\n")
OutFile.write(f"Birth Date:{c.date}\n")
OutFile.write(f"Address:{c.address}\n")
OutFile.write(f"HKID:{c.hkid}\n")
OutFile.write(f"Account value:{c.acc}\n")
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