如何在 Python 中为猜谜游戏添加范围系统？

Question

this is my first time asking on stack overflow and I'm quite new to programming. I just have a question on how to make 'guessing ranges. For example: Num is the number you have to guess

if guess > Num + 1 between Num + 5  
 print("That's really close") 

But I don't really know what to code to make it work, or if it's even possible. Basically what I want to do is to make the game print a text when you guess and it's near the Answer at a certain range eg 5

This is my code so far, and it works as expected:

#Author: Sunya Hatch-Barnwell
#Date: 6/02/2021
#Program: NumberGuess
import random
Guess = 0
Num = 1
choice = 0
min = 1
max = 0

print("Welcome to Number Guess")
max = int(input("What's the highest number you want?: "))

Num = random.randint(min, max)

while Guess != Num:

    Guess = int(input("Guess the number: "))
    if Guess == Num:
        print("That's correct the number was " ,Num )
    elif Guess > Num:
        print("Too high! ")
    elif Guess < Num:
        print("Too low! ")
    else:
        print("Please type a number! ")

Answer 1

If you mean "in a certain range" as in I was 4 numbers away from the guess, you could do it like this:

if abs(num - guess) < 5:
   print("You're within 4 numbers! Keep trying!") 

The abs() function is necessary, seeing as we can't use negative values for a distance from something in this context.

You can also remove the else statement in your code. Not only is the variable initialized (so the variable will always be greater or less than the guess), but the input forces a value in anyway before the conditionals.

Answer 2

So basically your looking for something like this?

min = 1
max = int(input('the maximum number?'))
cn = random.randint(min, max)

guess = int(input('guess the number!'))
if guess > cn:
    print('too high!')
elif cn > guess:
    print('too low!')
elif guess == cn:
    print('correct!')