如何从 python 中的 a.txt 文件中读取数据框中的大文本文件

Question

I have a large text file which has names and long paragraphs of statements made by several different people. the file format is.txt, I am trying to separate the name and the statement into two different columns of a data frame.

Data is in this format-

Harvey: I’m inclined to give you a shot. But what if I decide to go the other way?

Mike: I’d say that’s fair. Sometimes I like to hang out with people who aren’t that bright, you know, just to see how the other half lives.
Mike in the club
(mike speaking to jessica.)
Jessica: How are you mike?

Mike: good!
.....
....

and so on

the length of text file is 4million.

in the output I need a dataframe with one name column having the name of speaker and another statement column with that persons respective statement.

Answer 1

if: the format is always "name: one-liner-no-colon"
you could try:
df = pd.read_csv('untitled.txt',sep=': ', header=None)

or go manually:

f = open("untitled.txt", "r")
file_contents = []

current_name = ""
current_dialogue = ""

for line in f:
    splitted_line = line.split(": ")
    if len(splitted_line) > 1:
        # you are on a row with name: on it
        # first stop the current dialogue - save it
        if current_name:
            file_contents.append([current_name, current_dialogue])
        # then update the name encountered
        current_name = splitted_line.pop(0)
        current_dialogue = ""
    current_dialogue += ": ".join(splitted_line)    
# add the last dialogue line
file_contents.append([current_name, current_dialogue])

f.close()

df = pd.DataFrame(file_contents)
df

Answer 2

If you read the file line-by-line, you can use something like this to split the speaker from the spoken text, without using regex.

def find_speaker_and_text_from_line(line):
  split = line.split(": ")
  name = split.pop(0)
  rest = ": ".join(split)
  return name, rest