[英]ActiveMQ Java STOMP client receives SocketTimeoutException
There is an ActiveMQ server working on CentOS machine. CentOS 机器上有一个 ActiveMQ 服务器。 I can connect and consume messages with TCP and HTTP using the OpenWire JMS client.
我可以使用 OpenWire JMS 客户端与 TCP 和 HTTP 连接和使用消息。 However, When I tried with the ActiveMQ test STOMP client it throws this exception on
connection.receieve
;但是,当我尝试使用 ActiveMQ 测试 STOMP 客户端时,它会在
connection.receieve
上引发此异常;
java.net.SocketTimeoutException: Read timed out
at java.net.SocketInputStream.socketRead0(Native Method)
at java.net.SocketInputStream.socketRead(SocketInputStream.java:116)
at java.net.SocketInputStream.read(SocketInputStream.java:171)
at java.net.SocketInputStream.read(SocketInputStream.java:141)
at java.net.SocketInputStream.read(SocketInputStream.java:224)
at java.io.DataInputStream.readByte(DataInputStream.java:265)
at org.apache.activemq.transport.stomp.StompWireFormat.readHeaderLine(StompWireFormat.java:174)
at org.apache.activemq.transport.stomp.StompWireFormat.readLine(StompWireFormat.java:167)
at org.apache.activemq.transport.stomp.StompWireFormat.parseAction(StompWireFormat.java:200)
at org.apache.activemq.transport.stomp.StompWireFormat.unmarshal(StompWireFormat.java:112)
at org.apache.activemq.transport.stomp.StompConnection.receive(StompConnection.java:77)
at tr.com.estherial.stomplistener.StompListener.main(StompListener.java:25)
Listener Class监听器 Class
import org.apache.activemq.transport.stomp.Stomp;
import org.apache.activemq.transport.stomp.StompConnection;
import org.apache.activemq.transport.stomp.StompFrame;
public class StompListener {
public static void main(String[] args) {
StompConnection connection = new StompConnection();
try {
connection.open("host", 61613);
connection.connect("admin", "admin", "test");
connection.subscribe("TEST_TOPIC", Stomp.Headers.Subscribe.AckModeValues.CLIENT);
connection.begin("test");
while (true) {
try {
StompFrame message = connection.receive(10000);
System.out.println(String.format("%s - Receiver: received '%s'", new Date(), message.getBody()));
} catch (SocketTimeoutException e) {
// ignore
e.printStackTrace();
}
}
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
This is the connector in activemq.xml
:这是
activemq.xml
的连接器:
<transportConnectors>
<transportConnector name="stomp" uri="stomp://localhost:61613"/>
</transportConnectors>
Did you get similar exception before?您之前是否遇到过类似的异常?
The java.net.SocketTimeoutException
is expected when the STOMP subscriber receives no message within the specified timeout.当 STOMP 订阅者在指定的超时时间内未收到任何消息时,预计会出现
java.net.SocketTimeoutException
。 Once the client creates his subscription you need to send a message to the topic.客户创建订阅后,您需要向该主题发送消息。 At that point the client should receive the message and print it via your
System.out.println
.此时客户端应该收到消息并通过您的
System.out.println
打印它。
Also, in ActiveMQ 5.x when subscribing to a destination from a STOMP client you need to prefix the destination name with either /queue/
or /topic/
.此外,在 ActiveMQ 5.x 中,当从 STOMP 客户端订阅目的地时,您需要在目的地名称前加上
/queue/
或/topic/
前缀。 You aren't doing this in your application.您没有在您的应用程序中执行此操作。 Try using this:
尝试使用这个:
connection.subscribe("/topic/TEST_TOPIC", Stomp.Headers.Subscribe.AckModeValues.CLIENT);
Lastly, it's worth noting that you're using the test STOMP client from the ActiveMQ code-base.最后,值得注意的是,您正在使用 ActiveMQ 代码库中的测试STOMP 客户端。 This client is used by ActiveMQ's internal test-suite to verify the broker implementation is working as expected.
ActiveMQ 的内部测试套件使用此客户端来验证代理实现是否按预期工作。 It's not meant for general use.
它不适合一般用途。 Furthermore, if you're using Java you would be better off using a better performing and more full-featured client like the OpenWire JMS client or even the Qpid JMS client.
此外,如果您使用的是 Java,您最好使用性能更好、功能更全的客户端,例如 OpenWire JMS 客户端甚至 Qpid JMS 客户端。
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