使用嵌套键值的总和对嵌套字典进行排序

Question

So I am trying to sum the values of nested keys and sort the key values by this value. I have a nested dict like the following:

dict_items([('“The', {'T': 1}), ('reason', {'T': 1}), ('we', {'T': 1, 'O': 1}), ('have', {'T': 1, 'O': 1}),...

I want to sum the values associated with the keys 'O' and 'T' and then sort the words The , reason ... by the values produced by summing each of their 'O' and 'T' values so that I get a dict back with the word and its value.

So far I have the following which returns the counts of the words but not the words attached:

sorted([sum(i[1].values()) for i in dct.items()], reverse=True)

I have tried the following, but I get a key error with 'O'

my_word_dct = sorted(dct.items(), key = lambda x: x[1]['O'] + x[1]['T'], reverse = True)

Any ideas where I am going wrong?

EDIT: The expected output would be something like:

{'we':2, 'have':2, 'The':1, 'reason':1...}

Thanks in advance!!

Answer 1

You want the.get() function in case your dictionary doesn't have the key in question.

x[1].get('O',0) + x[1].get('T',0)