避免在 dplyr 中重复 as_tibble()

Question

Currently, I'm using multiple as_tibble(a_matrix) commands in my last line of code. To avoid repeating this command, what would be the shortest alternative?

(T1 = matrix(c(2,3,5,2, 3,4,4,5),4,2)  )      
colnames(T1) <- c("y1", "y2")

(T2 = matrix(c(4:6, 8,6,7),3,2)  )      
colnames(T2) <- colnames(T1) 

(T3 = matrix(c(7,8,10,9,7, 6,7,8,5,6),5,2)  )      
colnames(T3) <- colnames(T1) 

# bind rows of T1,T2 & T3 score matricies for the 3 groups:
(dat <- bind_rows(as_tibble(T1),as_tibble(T2),as_tibble(T3),.id = "group"))

Answer 1

Store the matrix in a list and convert it into a dataframe using map command.

list_df <- list(T1, T2, T3)
dat <- purrr::map_df(list_df, as.data.frame, .id = 'group')
dat

#   group y1 y2
#1      1  2  3
#2      1  3  4
#3      1  5  4
#4      1  2  5
#5      2  4  8
#6      2  5  6
#7      2  6  7
#8      3  7  6
#9      3  8  7
#10     3 10  8
#11     3  9  5
#12     3  7  6

Answer 2

With data.table

library(data.table)
list_df <- list(T1, T2, T3) 
rbindlist(lapply(list_df, as.data.frame), idcol = 'group')

---

Or using base R

lst1 <- mget(str_c('T', 1:3))
out <- do.call(rbind, Map(cbind, group = seq_along(lst1), lst1))

and apply the as_tibble once

as_tibble(out)