列表中的连续值（python）

Question

I am trying to find if the following list contains more than 4 consecutive values.

hours=[9,10,11,12,13,14,15]

I have tried this code and returns that the list above has more than 4 consecutive values but it does not work for other numbers.

hours=[9,28,11,23,13,9,15]
y = sorted(hours)
consecutive_hours = 0

while consecutive_hours <=4:
    for hours in hours:
        if len(y) == 7 and y[6]-y[0] == 6: 
            consecutive_hours += 1
        else:
            break

if consecutive_hours > 4:
    print("The list", hours, "contains more than 4 consecutive hours.")
else:
    print("The list",hours, "does not contain more than 4 consecutive hours.")

Answer 1

Try this!

hours = [9, 28, 11, 23, 13, 9, 15]
y = sorted(hours)

# Starts with 1 consecutive hour, we will subtract later
consecutive_hours = 1

# Check for the number of consecutive hours
for i in range(len(y)):
    if y[i] == y[i - 1] + 1:
        consecutive_hours += 1

if consecutive_hours == 1: consecutive_hours = 0

# Print results
if consecutive_hours > 4:
    print("The list ", hours, " contains more than 4 consecutive hours.")
else:
    print("The list ", hours, " does not contain more than 4 consecutive hours.")

Answer 2

You can try something like this

hours=[9,28,11,23,13,9,15]
y = sorted(hours)
consecutive_hours = 1

for i in range(0, len(y)):
        j = i + 1
        if j >= len(y):
            break
        if y[j] == y[i] + 1:
            consecutive_hours += 1
        elif consecutive_hours > 4:
            break
        else:
            consecutive_hours = 1

if consecutive_hours > 4:
    print("The list", hours, "contains more than 4 consecutive hours.")
else:
    print("The list",hours, "does not contain more than 4 consecutive hours.")

Answer 3

The following code will allow you to check if the next number in the list is the consecutive number to the current one the for loop is at, and if it is, it will add one to the consecutive_hours variable. If the for loop reaches a number that is not a consecutive number to the previous one, it will set consecutive_hours to 0 . If the consecutive_hours variable becomes greater than 4 before the for loop has iterated over the whole list, the for loop will break, and if the value is less than or equal to 4 when the loop reaches the end of the list, the loop will end. The following if statement after the for loop will check the consecutive_hours value, and print the appropriate statement.

hours=[9,28,11,23,13,14,15,16,17,9,15,1,2,3,4]
y = sorted(hours)
consecutive_hours = 0

for num in hours:
    if hours.index(num) == len(hours)-1:
        break
    elif hours[hours.index(num)+1] == num + 1:
        consecutive_hours += 1
        if consecutive_hours > 4:
            break
    else:
        consecutive_hours = 0

if consecutive_hours == 4:
    print("The list", hours, "contains more than 4 consecutive hours.")
else:
    print("The list",hours, "does not contain more than 4 consecutive hours.")

Answer 4

Without sorting, you could use the Counter class (from collections) to count how many matches you get when combining all values with their offsets by 0,1,2 and 3:

from collections import Counter
def maxConsec(hours,span=4):
    counts = Counter(h-i for h in {*hours} for i in range(span))
    return span in counts.values()

output:

maxConsec([9,10,11,12,13,14,15]) # True
maxConsec([9,28,11,23,13,9,15])  # False