使用 asyncio 运行协程后如何继续原始事件循环？

Question

I am creating a python script that basically retrieves information from a webpage and sending a message to a discord server.

I have a main file that basically goes

import asyncio
import discord
from dotenv import load_dotenv

def update(message:str):
    load_dotenv()
    TOKEN = os.getenv('DISCORD_TOKEN')
    GUILD = os.getenv('DISCORD_GUILD')

    client = discord.Client()

    @client.event
    async def on_ready():
        for guild in client.guilds:
            if guild.name == GUILD:
                break

        print(
            f'{client.user} is connected to the following guild:\n'
            f'{guild.name}(id: {guild.id})'
        )
        updatesChannel = client.get_channel([CHANNEL 1 ID HERE])
        await updatesChannel.send(message)
    client.run(TOKEN)

def log(message:str):
    load_dotenv()
    TOKEN = os.getenv('DISCORD_TOKEN')
    GUILD = os.getenv('DISCORD_GUILD')

    client = discord.Client()

    @client.event
    async def on_ready():
        for guild in client.guilds:
            if guild.name == GUILD:
                break

        print(
            f'{client.user} is connected to the following guild:\n'
            f'{guild.name}(id: {guild.id})'
        )
        serverLogChannel = client.get_channel([CHANNEL 2 ID HERE])
        await serverLogChannel.send(message)
    client.run(TOKEN)

while True:
    text = ['Text1', 'Text2']
    channel1text = text[0]
    channel2text = text[1]
    loop = asyncio.get_event_loop()
    loop.run_until_complete( update(channel1text) )

    loop = asyncio.get_event_loop()
    loop.run_until_complete( log(channel2text) )

Currently, the script will only send the message on the first channel, but not the second channel, and it does not continue with the While loop. Am I missing something here?

Answer 1

The core issue with your code is that client.run is a convenience synchronous function that will run the event loop, and run it forever, to keep the client going. That is also why your update function never returns. Incidentally, passing a synchronous function to run_until_complete doesn't work, and if update did return, you'd get an exception and Python wouldn't proceed to the next line.

To fix the issue, you can switch from client.run to client.start , which is async. You can also make use of the fact that both clients connect to the same token/guild and use only one client. That way the search for the guild can be done only once, and the log and update functions can be simplified to a simple channel.send . For example (untested):

async def send_message(client, channel_id, message):
    channel = client.get_channel(channel_id)
    await channel.send(message)

async def main():
    load_dotenv()
    TOKEN = os.getenv('DISCORD_TOKEN')
    GUILD = os.getenv('DISCORD_GUILD')

    client = discord.Client()
    asyncio.create_task(client.start(TOKEN))
    await client.wait_until_ready()
    for guild in client.guilds:
        if guild.name == GUILD:
            break
    print(
        f'{client.user} is connected to the following guild:\n'
        f'{guild.name}(id: {guild.id})'
    )

    while True:
        text = ['Text1', 'Text2']
        channel1text = text[0]
        channel2text = text[1]
        await send_message(client, [CHANNEL 1 ID], channel1text)
        await send_message(client, [CHANNEL 2 ID], channel2text)

if __name__ == '__main__':
    asyncio.run(main())