[英]Python subprocess different approaches
I have the following structure我有以下结构
- folder1
-- script1.py
- folder2
-- script2_1.py
-- script2_2.py
- folder2
-- script3.py
script2_1.py has the following line in it script2_1.py 中包含以下行
os.system("python3 script2_2.py "+str(id))
If I SSH into the instance, cd to folder2 and then run script2_1.py如果我 SSH 进入实例,cd到文件夹2然后运行script2_1.py
python3 script2_1.py
it works fine and script2_2.py is called as expected.它工作正常并且 script2_2.py 按预期调用。
Now in script1.py I want to call both script2_2.py and script3.py.现在在 script1.py 中,我想同时调用 script2_2.py 和 script3.py。 I've tested different approaches but no success yet.我测试了不同的方法,但还没有成功。
Approach 1 :方法1 :
id = str(id)
subprocess.check_call(["/folder2", "script2_2.py "+id])
subprocess.check_call(["/folder3", "script3.py "+id])
which gives这使
PermissionError: [Errno 13] Permission denied: '/folder2' PermissionError:[Errno 13] 权限被拒绝:'/folder2'
Approach 2:方法二:
id = str(id)
commands = '''
cd /folder2/
python3 script2_2.py {}
cd /folder3/
python3 script3.py {}
'''.format(id, id)
p = subprocess.Popen("/bin/sh", stdin=subprocess.PIPE, stdout=subprocess.PIPE)
out, err = p.communicate(commands.encode('utf-8'))
which gives这使
/bin/sh: python3: not found /bin/sh: python3: 未找到
Approach 3:方法3:
id = str(id)
subprocess.call(['cd /folder2/','python3 script2_2.py {}'.format(id)])
subprocess.call(['cd /folder3/','python3 script3.py {}'.format(id)])
which gives这使
FileNotFoundError: [Errno 2] No such file or directory: 'cd /folder2/': 'cd /folder2/' FileNotFoundError:[Errno 2] 没有这样的文件或目录:'cd /folder2/':'cd /folder2/'
Approach 4 :方法4 :
In this one I've tested args with both string and list, specifying the full path to the.py file, with and without shell=True, without sys.path and with full path in subprocess.call, ...在这一个中,我用字符串和列表测试了 args,指定了 .py 文件的完整路径,有和没有 shell=True,没有 sys.path 和 subprocess.call 中的完整路径,...
id = str(id)
#import sys
#sys.path.insert(1, '/folder2/')
subprocess.call(['/usr/local/bin/python3','/folder2/script2_2.py {}'.format(id)])
#sys.path.insert(1, '/folder3/')
subprocess.call(['/usr/local/bin/python3','/folder3/script3.py {}'.format(id)])
which gives这使
/usr/local/bin/python3: can't open file '/folder2/script2_2.py 80': [Errno 2] No such file or directory /usr/local/bin/python3: 无法打开文件'/folder2/script2_2.py 80': [Errno 2] 没有这样的文件或目录
/usr/local/bin/python3: can't open file '/folder3/script3.py 80': [Errno 2] No such file or directory /usr/local/bin/python3: 无法打开文件'/folder3/script3.py 80': [Errno 2] 没有这样的文件或目录
Eventually I manage to solve it by using and adaptation of Approach 2 with the full path to python3.最终,我设法通过使用和改编方法 2以及到 python3 的完整路径来解决它。
id = str(id)
commands = '''
cd /folder2/
/usr/local/bin/python3 script2_2.py {}
cd /folder3/
/usr/local/bin/python3 script3.py {}
'''.format(id, id)
p = subprocess.Popen("/bin/sh", stdin=subprocess.PIPE, stdout=subprocess.PIPE)
out, err = p.communicate(commands.encode('utf-8'))
To know which one is I SSH into the instance and ran要知道哪个是我 SSH 进入实例并运行
which python3
which returned返回
/usr/local/bin/python3
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