[英]Oracle XMLTYPE extract based on value and condition
SELECT * FROM v$version;
Oracle Database 12c Enterprise Edition Release 12.1.0.2.0 - 64bit Production
PL/SQL Release 12.1.0.2.0 - Production
"CORE 12.1.0.2.0 Production"
TNS for Linux: Version 12.1.0.2.0 - Production
NLSRTL Version 12.1.0.2.0 - Production
I have sample Query with XML like below:我有 XML 的示例查询,如下所示:
with t(xml) as
(
select xmltype(
'<SSO_XML
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
TimeStamp="2020-08-05T21:57:23Z"
Target="Production"
Version="1.0"
TransactionIdentifier="PLAN_A"
SequenceNmbr="123456"
xmlns="http://www.w3.org/2001/XMLSchema">
<PlanCode PlanCodeCode="CHOICE">
<S_DAYS PCODE="P123">
<STUDENT>
<DIVISION Amount="150.05" Code="Flat" S_CODE="1" />
<DIVISION Amount="250.05" Code="Flat" S_CODE="2" />
</STUDENT>
</S_DAYS>
<S_DAYS PCODE="P1234">
<STUDENT>
<DIVISION Amount="150.05" Code="Flat" S_CODE="1" />
<DIVISION Amount="250.05" Code="Flat" S_CODE="2" />
</STUDENT>
</S_DAYS>
<S_DAYS PCODE="Child1">
<AdditonalFare>
<AdditonalFareAmount Amount="100"/>
</AdditonalFare>
</S_DAYS>
<S_DAYS PCODE="Child2">
<AdditonalFare>
<AdditonalFareAmount Amount="130"/>
</AdditonalFare>
</S_DAYS>
</PlanCode>
</SSO_XML>')
from dual
)
select h.PlanCodeCode
,b.*
from t
cross join
xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'/SSO_XML'
passing t.xml
columns PlanCodeCode varchar2(100) path './PlanCode/@PlanCodeCode',
attributes xmltype path './PlanCode'
) h
left join xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'PlanCode/S_DAYS/STUDENT/DIVISION'
passing h.attributes
columns node_level for ordinality
, amount number path '@Amount'
, pcode varchar2(10) path './../../@PCODE'
, child1_amount number path './../../@Amount[1]' --->Child1
, child2_amount number path './../../@Amount[2]' --->Child2
) b on 1=1;
The XML expected to have S_DAYS node with STUDENT -> DIVISION, we fetch Amount value from the XML. XML 预计会有 S_DAYS 节点和 STUDENT -> DIVISION,我们从 XML 获取金额值。
There are optional node(s) S_DAYS with S_DAYS with PCODE="Child1" or PCODE="Child2"有可选节点 S_DAYS 与 S_DAYS 与 PCODE="Child1" 或 PCODE="Child2"
When node PCODE for Child1 or Child2 is present, we have to apply for existing rows itself.当 Child1 或 Child2 的节点 PCODE 存在时,我们必须自己申请现有的行。
Actual Result:实际结果:
Expected Result:预期结果:
Any help will be much appreciated.任何帮助都感激不尽。 Thanks.
谢谢。
You can walk back up to the sibling of the student s_days
node:您可以回到学生
s_days
节点的兄弟节点:
select h.PlanCodeCode, b.amount, b.pcode, b.child1_amount, b.child2_amount
from t
cross join
xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'/SSO_XML'
passing t.xml
columns PlanCodeCode varchar2(100) path './PlanCode/@PlanCodeCode',
attributes xmltype path './PlanCode'
) h
left join xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'PlanCode/S_DAYS/STUDENT/DIVISION'
passing h.attributes
columns node_level for ordinality
, amount number path '@Amount'
, pcode varchar2(10) path './../../@PCODE'
, child1_amount number path './../../../S_DAYS[@PCODE="Child1"]/AdditonalFare/AdditonalFareAmount/@Amount'
, child2_amount number path './../../../S_DAYS[@PCODE="Child2"]/AdditonalFare/AdditonalFareAmount/@Amount'
) b on 1=1;
Or you can get the children from the first XMLTable, if you always want to see them even if there are no student nodes:或者,您可以从第一个 XMLTable 中获取孩子,如果即使没有学生节点也总是想查看它们:
select h.PlanCodeCode, b.amount, b.pcode, h.child1_amount, h.child2_amount
from t
cross join
xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'/SSO_XML'
passing t.xml
columns PlanCodeCode varchar2(100) path './PlanCode/@PlanCodeCode',
attributes xmltype path './PlanCode',
child1_amount number path './PlanCode/S_DAYS[@PCODE="Child1"]/AdditonalFare/AdditonalFareAmount/@Amount',
child2_amount number path './PlanCode/S_DAYS[@PCODE="Child2"]/AdditonalFare/AdditonalFareAmount/@Amount'
) h
left join xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'PlanCode/S_DAYS/STUDENT/DIVISION'
passing h.attributes
columns node_level for ordinality
, amount number path '@Amount'
, pcode varchar2(10) path './../../@PCODE'
) b on 1=1;
Incidentally, as you're on 12c you can use cross apply
and outer apply
- the latter instead of the outer join with dummy on 1=1
condition.顺便说一句,当您在 12c 上时,您可以使用
cross apply
和outer apply
- 后者而不是on 1=1
条件下使用 dummy 进行外部连接。
select h.PlanCodeCode, b.amount, b.pcode, h.child1_amount, h.child2_amount
from t
cross apply
xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'/SSO_XML'
passing t.xml
columns PlanCodeCode varchar2(100) path './PlanCode/@PlanCodeCode',
attributes xmltype path './PlanCode',
child1_amount number path './PlanCode/S_DAYS[@PCODE="Child1"]/AdditonalFare/AdditonalFareAmount/@Amount',
child2_amount number path './PlanCode/S_DAYS[@PCODE="Child2"]/AdditonalFare/AdditonalFareAmount/@Amount'
) h
outer apply xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'PlanCode/S_DAYS/STUDENT/DIVISION'
passing h.attributes
columns node_level for ordinality
, amount number path '@Amount'
, pcode varchar2(10) path './../../@PCODE'
) b;
Any of those get the same result with your sample data:其中任何一个都与您的样本数据得到相同的结果:
PLANCODECODE | AMOUNT | PCODE | CHILD1_AMOUNT | CHILD2_AMOUNT
:----------- | -----: | :---- | ------------: | ------------:
CHOICE | 150.05 | P123 | 100 | 130
CHOICE | 250.05 | P123 | 100 | 130
CHOICE | 150.05 | P1234 | 100 | 130
CHOICE | 250.05 | P1234 | 100 | 130
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