捕获 runpy.run_module 标准输出

Question

I'm unable to capture stdout of runpy.run_module into a variable using StringIO.
To demonstrate the problem, I created a script called runpy_test.py (code below) using an arg switch;

• 0 = do not redirect stdout.
• 1 = redirect using StringIO, capture into variable, print variable.

Console Output

(base) PS C:\Users\justi\Documents> python .\runpy_test.py 0  
pip 20.0.2 from C:\ProgramData\Anaconda3\lib\site-packages\pip (python 3.6)  
(base) PS C:\Users\justi\Documents> python .\runpy_test.py 1  
(base) PS C:\Users\justi\Documents>  

I was expecting python.\runpy_test.py 1 to print pip 20.0.2 from C:\ProgramData\Anaconda3\lib\site-packages\pip (python 3.6) , but as you can see from the above console capture, I'm getting nothing.

runpy_test.py

import io
import sys
import runpy
import copy

capture_stdout = bool(sys.argv[1] == "1")
if capture_stdout:
    _stdout = sys.stdout
    sys.stdout = io.StringIO()
_argv = copy.deepcopy(sys.argv)
sys.argv = ['', '-V']
runpy.run_module("pip", run_name="__main__")
sys.argv = _argv
if capture_stdout:
    result = sys.stdout.getvalue()
    sys.stdout = _stdout
    print(f"result: {result}")

I'm guessing sys.stdout is not being correctly re-initialised before I print because of something related to runpy.run_module , but not really sure how to debug. Any ideas would be great, solutions even better.
My environment is Python 3.6.10 using conda 4.8.3.
Thanks in advance.

Answer 1

Using subprocess.check_output instead of runpy.run_module solved my problem.
See Installing python module within code