如何在 models.py 中获取当前用户？

Question

Hi I am trying to add the User column to know which User added the tool in the tools/model.py page

tools_name = models.CharField('Tool\'s Name', max_length=100, unique=True)
tools_project = models.ForeignKey(Project, on_delete=models.DO_NOTHING, null=True, blank=True, limit_choices_to=~Q(project_status=2), verbose_name='Project\'s Name')
user = models.CharField(max_length=100, editable=False)

But I want to know how to save the user that created or updated the tool?

Answer 1

Models are normally request unaware , so you should not do this. This is a task that belongs in the view. Furthermore normally you work with a ForeignKey or a OneToOneField or another relation. This is useful since users might eventually change their (user)name. By storing the username, your database can contain a username that no longer exists or even worse: another user now uses that username and the use got then access to the models of the previous "owner".

Your model thus looks like:

from user.conf import settings

class MyModel(models.Model):
    tools_name = models.CharField('Tool\'s Name', max_length=100, unique=True)
    tools_project = models.ForeignKey(
        Project,
        on_delete=models.DO_NOTHING,
        null=True,
        blank=True,
        limit_choices_to=~Q(project_status=2),
        verbose_name='Project\'s Name'
    )
    user = models.
        settings.AUTH_USER_MODEL,
        on_delete=models.CASCADE,
        editable=False
    

You can work with a ModelForm for example and then let the view set the user:

from django.contrib.auth.decorators import login_required
from django.shortcuts import redirect

@login_required
def my_view(request):
    if request.method == 'POST':
        form = MyModelForm(request.POST, request.FILES)
        if form.is_valid():
            form
            form.save()
            return redirect('name-of-some-view')
    else:
        form = MyModelForm()
    return render(request, 'name-of-some-template.html', {'form': form})

For the ModelAdmin you can override the .save_model(…) method [Django-doc] :

from django.contrib import admin

@admin.register(MyModel)
class MyModelAdmin(admin.ModelAdmin):

    def save_model(self, request, obj, form, change):
        obj
        super().save_model(request, obj, form, change)