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Java OffsetDateTime.parse() 将额外的零添加到时间

[英]Java OffsetDateTime.parse() adds extra zeros to time

This following codes return an OffsetDateTime like this 2021-06-30T23:59:59.009966667Z, with 2 extra zeros added.以下代码返回一个 OffsetDateTime,如 2021-06-30T23:59:59.009966667Z,添加了 2 个额外的零。 I have 7 n's in the formatter, but it still returns 9 digits.我在格式化程序中有 7 个 n,但它仍然返回 9 个数字。 Why?为什么?

import java.time.OffsetDateTime;
import java.time.format.DateTimeFormatter;

public class HelloWorld{

     public static void main(String []args){
         DateTimeFormatter MAIN_FORMATTER = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.nnnnnnn XXX");
         String dbData = "2021-06-30 23:59:59.9966667 +00:00";
         OffsetDateTime time = OffsetDateTime.parse(dbData, MAIN_FORMATTER);
         System.out.println(time.toString());
     }
}

This following codes return an OffsetDateTime like this 2021-06-30T23:59:59.009966667Z, with 2 extra zeros added.以下代码返回一个 OffsetDateTime,如 2021-06-30T23:59:59.009966667Z,添加了 2 个额外的零。 I have 7 n's in the formatter, but it still returns 9 digits.我在格式化程序中有 7 个 n,但它仍然返回 9 个数字。 Why?为什么?

You will get the same result even for a single n or any number of n s less than or equal to 7 .即使对于单个n或任何数量小于或等于7n ,您也会得到相同的结果。 However, if you exceed 7 , you will get an exception something like但是,如果您超过7 ,您将收到类似的异常

Exception in thread "main" java.time.format.DateTimeParseException:
               Text '2021-06-30 23:59:59.9966667 +00:00' could not be parsed at index 20

The reason for this is DateTimeFormatter counts the number of n in the pattern and if it is less than or equal to the number of digits after .这样做的原因是DateTimeFormatter计算模式中n的数量,如果它小于或等于之后的位数. , it will use additional n to compensate that but if the number of n s exceed the number of digits, it won't have any clue what that additional n s are for. ,它将使用额外的n来补偿,但如果n的数量超过位数,它将不知道额外的n的用途。

It's not just for n but for most (if not all) of the symbols.它不仅适用于n ,而且适用于大多数(如果不是全部)符号。 You can understand it from the following example:您可以从以下示例中理解它:

import java.time.LocalDate;
import java.time.format.DateTimeFormatter;
import java.util.Locale;

public class Main {
    public static void main(String[] args) {
        String strDate1 = "2020/2/2";
        String strDate2 = "2020/02/02";

        // Notice the single M and d
        DateTimeFormatter dtfCorrectForBothDateStrings = DateTimeFormatter.ofPattern("uuuu/M/d", Locale.ENGLISH);
        System.out.println(LocalDate.parse(strDate2, dtfCorrectForBothDateStrings));
        System.out.println(LocalDate.parse(strDate1, dtfCorrectForBothDateStrings));

        // Notice the two M's and d's
        DateTimeFormatter dtfCorrectOnlyForSecondDateString = DateTimeFormatter.ofPattern("uuuu/MM/dd", Locale.ENGLISH);
        System.out.println(LocalDate.parse(strDate2, dtfCorrectOnlyForSecondDateString));
        System.out.println(LocalDate.parse(strDate1, dtfCorrectOnlyForSecondDateString));
    }
}

Output: Output:

2020-02-02
2020-02-02
2020-02-02
Exception in thread "main" java.time.format.DateTimeParseException: Text '2020/2/2' could not be parsed at index 5
    at java.base/java.time.format.DateTimeFormatter.parseResolved0(DateTimeFormatter.java:2051)
    at java.base/java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1953)
    at java.base/java.time.LocalDate.parse(LocalDate.java:429)
    at Main.main(Main.java:16)

Why does it give me .009966667 and not .9966667 ?为什么它给我.009966667而不是.9966667

The symbol, n stands for nano-of-second and 9966667 nanoseconds are equal to 0.009966667 second.符号n代表纳秒9966667纳秒等于0.009966667秒。

public class Main {
    public static void main(String[] args) {
        int nanos = 9966667;
        System.out.println(nanos + " nanoseconds = " + ((double) nanos / 1_000_000_000) + " second");
    }
}

Output: Output:

9966667 nanoseconds = 0.009966667 second

How does it work with S ?它如何与S一起工作?

S stands for fraction-of-second and .9966667 is parsed as 0.9966667 second. S代表秒的分数.9966667被解析为0.9966667秒。

A note on OffsetDateTime#toString implementation:关于OffsetDateTime#toString实现的注释:

The OffsetDateTime#toString groups the digits of fraction-of-second in the nearest multiple of 3 (ie milli, micro and nano) eg OffsetDateTime#toString以最接近3的倍数(即毫、微和纳米)对秒的小数位数进行分组,例如

  • for .99 , the output will be .990 , and对于.99 , output 将为.990 ,并且
  • for .996 , the output will be .996 , and对于.996 , output 将为.996 ,并且
  • for .9966 , the output will be .996600 , and对于.9966 , output 将为.996600 ,并且
  • for .9966667 , the output will be .996666700 .对于.9966667 , output 将为.996666700

Given below is an excerpt from OffsetDateTime#toString :下面给出了OffsetDateTime#toString的摘录:

The output will be one of the following ISO-8601 formats: output 将是以下 ISO-8601 格式之一:

  • uuuu-MM-dd'T'HH:mmXXXXX uuuu-MM-dd'T'HH:mmXXXXXX
  • uuuu-MM-dd'T'HH:mm:ssXXXXX uuuu-MM-dd'T'HH:mm:ssXXXXX
  • uuuu-MM-dd'T'HH:mm:ss.SSSXXXXX uuuu-MM-dd'T'HH:mm:ss.SSSXXXXXX
  • uuuu-MM-dd'T'HH:mm:ss.SSSSSSXXXXX uuuu-MM-dd'T'HH:mm:ss.SSSSSSXXXXXX
  • uuuu-MM-dd'T'HH:mm:ss.SSSSSSSSSXXXXX uuuu-MM-dd'T'HH:mm:ss.SSSSSSSSSXXXXX

The final demo (incorporating all that have been discussed above):最后的演示(包含上面讨论的所有内容):

import java.time.OffsetDateTime;
import java.time.format.DateTimeFormatter;
import java.util.Locale;

public class Main {
    public static void main(String[] args) {
        String strDateTime = "2021-06-30 23:59:59.9966667 +00:00";

        System.out.println(OffsetDateTime.parse(strDateTime,
                DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.nnnnnnn XXX", Locale.ENGLISH)));

        System.out.println(OffsetDateTime.parse(strDateTime,
                DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.SSSSSSS XXX", Locale.ENGLISH)));
    }
}

Output: Output:

2021-06-30T23:59:59.009966667Z
2021-06-30T23:59:59.996666700Z

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