检查一个句子是否连续包含多个单词（Python）

Question

I want to write a function that checks if a given sentence contains given words. For example:

my_string = 'Biden'
sentence = 'Biden is the new president of the United States.'

if my_string.lower() in sentence.lower().split():
    print('Sentence contains string')
else:
    print('Sentence does not contain string')

This example would return True. Now a problem arises once the string isn't just a single word.

my_string = 'Joe Biden'
sentence = 'Joe Biden is the new president of the United States.'

if my_string.lower() in sentence.lower().split():
    print('Sentence contains string')
else:
    print('Sentence does not contain string')

Here it would return False. Is there simple solution for this problem?

Answer 1

You could use a regular expression - the thing you're looking for encapsulated by word-boundaries:

import re

word = "Joe Biden"
pattern = f"\\b{word}\\b"

sentence = "Joe Biden is the new president of the United States"
match = re.search(pattern, sentence, re.IGNORECASE)

print(f"Sentence {('contains', 'does not contain')[match is None]} string")

Answer 2

Try

my_string = 'Joe Biden'
sentence = 'Joe Biden is the new president of the United States.'
my_string = my_string.split()
sentence = sentence.split()
confirm = []
for i in sentence:
  if i in my_string:
    confirm.append(i)
if confirm == my_string:
  if sentence.find(my_string) != 0 - 1:
    # my_string is in sentence
    pass

This should work with your problem and your various requirements.

Original:

my_string = 'Joe Biden'
sentence = 'Joe Biden is the new president of the United States'
if sentence.find(my_string) != 0 - 1:
  # my_string is in sentence
  pass

Answer 3

Try that:

    my_string = 'Joe Biden'
sentence = 'Joe Biden is the new president of the United States.'

if my_string.lower() in sentence.lower(): 
    print('Sentence contains string')
else:
    print('Sentence does not contain string')