为什么循环中'i'的值与for循环中初始化的值不冲突

Question

The value of i is not conflicting with the value of i initialized inside the loop, why is it so?

#include <stdio.h>
    
int main()
{
    for (int i = 0; i < 5 ; i++)
    {
        int i = 10;
        printf("%d \t", i);
        i--;
    }

    return 0;
}

Answer 1

The variable i was initialized as zero in the loop. Now, when the loop iteration begins, the identically named variable i inside the braces shadows the original one (defined outside of the braces).

Since it was initialized to 10, the program displays 10 , then it is decremented by one later that doesn't affect the output because the shadowed int i = 10; is executed in each iteration. This will keep happening 5 times.

Here's a demo .