如何在 C 中将 int 添加到 char

Question

I'm trying to add an int to each char in a char array but I don't know how to do that.

void Offset(char sirDeCaractere[100], int x)
{
    int i = 0;
    while (sirDeCaractere[i] != '\0')
    {
        sirDeCaractere[i] += x;
        i++;
    }
    printf("%c", sirDeCaractere[i]);
}

I've been trying to do something like this for a while, but I can't figure it out. Written like this I don't think it will work due to pointer arithmetic, but I have no other ideas.

For example:

Input:
sirDeCaractere = cuvant
x = 5
Output:
hz{fsy

How should I edit my code in order to achieve the desired output?

Right now my program is crashing (as I said, because sirDeCaractere[i] += x; is pointer arithmetic).

Thanks.

Answer 1

You want this:

#include <stdio.h>

void Offset(char sirDeCaractere[100], int x)
{
    int i = 0;
    while (sirDeCaractere[i] != '\0')
    {
        sirDeCaractere[i] += x;
        i++;
    }
    // remove this line, it makes no sense    printf("%c", sirDeCaractere[i]);
}

int main(void)
{
   char test[] = "ABCD";
   Offset(test, 1);
   printf("%s\n", test);
}

Output:

BCDE

I guess the code you didn't show is something like this:

...
char *test = "ABCD";
Offset(test, 1);
...

or

Offset("ABCD", 1);

which will crash on most platforms. Read this form more information: Why do I get a segmentation fault when writing to a "char *s" initialized with a string literal, but not "char s[]"?

Bonus:

Be aware that the [100] below is useless:

void Offset(char sirDeCaractere[100], int x)

you can write:

void Offset(char sirDeCaractere[], int x)

or:

void Offset(char *sirDeCaractere, int x)

which do exactly the same thing.