简体   繁体   English

使用 Python ElementTree 在另一个 xml 文件的节点中插入 xml 文件

[英]Insert an xml file in a node of another xml file using Python ElementTree

I have two xml files, where A references B. I would like a way to combine them into single xml file in Python.我有两个 xml 文件,其中 A 引用 B。我想要一种方法将它们组合成 Python 中的单个 xml 文件。

FileA.xml文件A.xml

    <FileAServices>
            <Services ref="FileB.xml" xpath="Services"/>
    </FileAServices>

FileB.xml文件B.xml

    <Services>
            <ThreadName>FileBTask</ChangeRequestName>
    </Services>

Output Output

    <FileAServices>
         <Services>
                 <ThreadName>FileBTask</ThreadName>
         </Services>
    </FileAServices>

I've only gotten as far as below.我只到了下面。 I don't know how to assign the entire tree to elem.我不知道如何将整个树分配给 elem。

import xml.etree.ElementTree as ET
base = ET.parse('FileA.xml')
ref = ET.parse('FileB.xml')
root = base.getroot()
subroot = ref.getroot()
for elem in root.iter('Services'):
    elem.attrib = {}
    for subelem in subroot.iter():
        subdata = ET.SubElement(elem, subelem.text)
        if subelem.attrib:
            for k, v in subelem.attrib.items():
                subdata.set(k, v)

Just use elem.clear() and elem.append(...) .只需使用elem.clear()elem.append(...)

from io import StringIO, BytesIO
import xml.etree.ElementTree as ET

a = b'''\
<FileAServices>
  <Services ref="FileB.xml" xpath="Services"/>
</FileAServices>\
'''

b = b'''\
<Services>
  <ThreadName>FileBTask</ThreadName>
</Services>\
'''

base = ET.parse(BytesIO(a))
ref = ET.parse(BytesIO(b))
root = base.getroot()
subroot = ref.getroot()

elem = root.find('Services')
elem.clear()
for subelem in subroot.iter('ThreadName'):
    elem.append(subelem)

out = BytesIO()
base.write(out, 'UTF-8')
print(out.getvalue().decode('UTF8'))

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM