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Swift 组合接收器阵列 AnyPublisher

[英]Swift Combine Sink Array AnyPublisher

I would like to wait for data from all elements and combine them into one result:我想等待所有元素的数据并将它们组合成一个结果:

Item: AnyPublisher <Int, Swift.Error>
Array: AnyPublisher <[Result<Int, Swift.Error>], Never>

Can this be done somehow?这可以以某种方式完成吗? I've tried using Zip and Merge - but I couldn't get the desired result.我已经尝试使用 Zip 和 Merge - 但我无法获得预期的结果。

Example:例子:

func createItem(num: Int) -> AnyPublisher<Int, Swift.Error> {
    Just(num)
        .setFailureType(to: Swift.Error.self)
        .eraseToAnyPublisher()
}
func createItems(nums: [Int]) -> AnyPublisher<[Result<Int, Swift.Error>], Never> {
    Publishers.MergeMany(nums.map { self.createItem(num: $0) } )
        .collect()
        .eraseToAnyPublisher()
}

Function but "createItems" does not work Function 但“createItems”不起作用

Looks like you want to generate an array of results - whether a value or an error - emitted by each publisher for each array value.看起来您想要生成一个结果数组 - 无论是值还是错误 - 由每个发布者为每个数组值发出。

MergeMany + Collect is the right approach here. MergeMany + Collect是正确的方法。 MergeMany will complete only when all its input publishers complete, and .collect() will for for that completion event before emitting. MergeMany仅在其所有输入发布者完成时才会完成,并且.collect()将在发出之前针对该完成事件。

Using your example:使用您的示例:

func createItems(nums: [Int]) -> AnyPublisher<[Result<Int, Error>], Never> {

    let publishers = nums.map { v -> AnyPublisher<Result<Int, Error>, Never> in
        createItem(num: v) // AnyPublisher<Int, Error>
           .first() // ensure a single result
           .map { .success($0) } // map value to .success result
           .catch { Just(.failure($0)) } // map error to .failure result
           .eraseToAnyPublisher()
    }

    return Publishers.MergeMany(publishers)
        .collect() // wait for MergeMany to complete
        .eraseToAnyPublisher()
}

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