[英]how to create tuples with below 2 list in given order
A=[1,2,3]
B=[4,5,6]
o/p : [(1,6).(2,5),(3,6)]
how I can achieve above output.我如何才能实现上述 output。 as i have tried using zip but its giving first element of first list with 1st element of second list.
正如我尝试使用 zip 但它给出了第一个列表的第一个元素和第二个列表的第一个元素。
You can zip with the second list reversed()
:您可以使用第二个列表
reversed()
zip :
>>> A=[1,2,3]
>>> B=[4,5,6]
>>> list(zip(A, reversed(B)))
[(1, 6), (2, 5), (3, 4)]
This won't put them in a (a, b)
format, but at least they are in the right order.这不会将它们置于
(a, b)
格式中,但至少它们的顺序正确。
A = [1,2,3]
B = [4,5,6]
C = [tup for i in range(3) for tup in (A[i], B[- i - 1])]
Printing C
outputs: [1, 6, 2, 5, 3, 4]
.打印
C
输出: [1, 6, 2, 5, 3, 4]
。
Here is how to create the tuples with a given order.以下是如何创建具有给定顺序的元组。
A = [1, 2, 3]
B = [4, 5, 6]
C = [(A[i], value) for i, value in enumerate(B[::-1])]
And this yields the values in C这会产生 C 中的值
[(1, 6), (2, 5), (3, 4)]
a = [1,2,3]
b = [4, 5, 6]
list(zip(a, reversed(b)))
[(1, 6), (2, 5), (3, 4)]
keys = ["name", "age"]
values = ["wanglei", 30]
dict(zip(keys, values))
{'name': 'wanglei', 'age': 30}
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