正则表达式允许长度限制为 5 的所有字符？

Question

I have a sentence,

  let message = "Hi thank you for #num#num bye"

Here in place of #num, there can be any values but atleast 1 and maximum 5 characters can be there. So here is how I'm replacing the #num like below.

  Hi thank you for .{1,5}.{1,5} bye

So Im forming the regex like below,

 let regex =  /^Hi\s*thank\s*you\s*for\s*.{1,5}.{1,5} bye$/i

 let usermsg = "Hi thankyou for 6 bye"

Ideally the above one should fail since I have substituted only one value. Minimium there should be 2 values.

but when I try to test using below,

  console.log(regex.test(usermsg) ? "Pass" : "Fail", "==>", usermsg );

It is failing. Kindly help me on this.

Answer 1

You are almost there. The only issue is that with \s* after 'for' you allow zero or more space characters. So with your test message, the space in ' 6' is considered as 1 character part of the first .{1,5} group.

Changing \s* to \s+ will solve your problem.
+ matches one or more characters

Solution -

let regex =  /^Hi\s*thank\s*you\s*for\s+.{1,5}.{1,5} bye$/i

Here is a nice tool to test your regex and debug - https://regex101.com/