将 gradle 命令行 arguments 传递给 application.properties

Question

I have a Spring Boot Gradle application and many MySQL servers and databases. In different scenarios, I want to start the application with different databases or create them if they do not exist. I want to use this mechanism with command line arguments. The URL for database is stored in application.properties file of Spring:

spring.datasource.url=jdbc:mysql://localhost:3306/mydb1?createDatabaseIfNotExist=true&useSSL=true

I want to run gradle with command line arguments that will apply to the application.properties file so in my head will be something like this.

application.properties: spring.datasource.url=jdbc:mysql://${linkNewDB}?createDatabaseIfNotExist=true&useSSL=true

And to run the program as: gradle bootRun -Pargs=--linkNewDB="someNewDB:3309"

Does anybody know how can I achieve this mechanism? I tried different options but none of them worked. Thanks!

Answer 1

How about changing the whole URL, like this:

gradle bootRun --args='--spring.datasource.url=jdbc:mysql://someNewDB:3309?createDatabaseIfNotExist=true&useSSL=true'

reference: https://docs.spring.io/spring-boot/docs/current/gradle-plugin/reference/htmlsingle/#running-your-application.passing-arguments