如何在保留所有元素的同时提取字典列表中的所有键？ （Python）

Question

Suppose I have the following list of dictionaries:

list1 = [{'1': 1}, {'1': 1}, {'0': 1}, {'1': 1}, {'1': 1}, {'0': 1}]

how can I extract all the keys into a single list? The desired output should look like:

li = [1,1,0,1,1,0]

I tried to use

randlis = [list[i].keys() for i in range len(list1)]

This doesn't work since the output includes the type:

[dict_keys(['1']), dict_keys(['1']), dict_keys(['0'])]

Thanks!

Answer 1

You can simply loop over the elements using list comprehension

[key for _dict in list for key in _dict.keys()]
#['1', '1', '0', '1', '1', '0']

Note. You should not use list or str int etc for naming variables. I have kept it the same in the example so you understand the loop better. Please change your var name to something else.

Answer 2

You can use chain from itertools:

list1 = [{'1': 1}, {'1': 1}, {'0': 1}, {'1': 1}, {'1': 1}, {'0': 1}]

from itertools import chain

randlis = list(chain(*list1))

print(randlis)
['1', '1', '0', '1', '1', '0']