读取文件并将其转换为字典

Question

I have this text file:

this is name_of_liquid(string)=amount(int)

liquid1=200

liquid2=20

liquid_X_= empty

liquid_3= 3000

now, the name does not really matter however the amount does. It has to be an int. If it is any other type beside int the program would raise an exception

Here is my code/ pseudocode:

#opening the file
d={}

try:
  dic = {}
  with open('accounts.txt') as f:
     for line in f:
        (key , val) = line.split()
        d[key] = int(val)
#except ValueError:
#    print('The value for', key,'is', value,' which is not a number!')

the except block is commented because that is my pseudocode and how I planed in handling the error, but when I run this code without using exception handling, I get an error of 'not enough values to unpack' Can anyone please help me?

Answer 1

Try this

f = open("acounts.txt", "r")
dict = {}

try:
    for line in f:
        line = line.split("=")
        dict[line[0]] = int(line[1])
except:
print("Invalid value for key.")

Answer 2

You should split the lines with = as delimiter and strip the list to get rid of extra whitespaces.

I personally think that the try catch block should be used while adding elements to the dictionary.

The following code should work for your problem.

d = {}
with open('accounts.txt', 'r') as f:
    for line in f:
        (key , val) = map(str.strip,line.split("="))
        try:
            d[key] = int(val)
        except ValueError:
            print('The value for', key,'is', val,' which is not a number!')