如何通过忽略数字中的句点的标点符号分割字符串

Question

I'm using the following code in javascript to split string into phrases.

var result = str.match( /[^\n\.!\?\;:]+[\n\.!\?\;:]+/g );
let elements = result.map(element => element.trim());
elements = elements.filter(function (el) {return el != null && el != "";});

It works ok. My problem is when the string has numbers in the thousands marked with a dot that some people use like 1.500. How can alter this so that it only separates the phrases if the punctuation is followed by a space.

Answer 1

You can use

/(?:[^\n.!?;:]|[\n.!?;:](?!\s))+[\n.!?;:]+/g

See the regex demo . The point is that you either match any char other than the punctuation of your choice, or a punctuation not followed with a whitespace, one or more times, and then one or more punctuation symbols of your choice.

Details :

• (?: - start of a non-capturing group:
  • [^\n.?;::] - any char but a newline, . , ! , ? , ; or :
• | - or
  • [\n.?;:?](?!\s) - a newline, . , ! , ? , ; or : not followed with a whitespace
• )+ - one or more times
• [\n.?;::]+ - one or more newline, . , ! , ? , ; or : chars.

See a JavaScript demo:

 var s = 'It works ok. My problem is when the string has numbers in the thousands marked with a dot that some people use like 1.500. How can alter this so that it only separates the phrases if the punctuation is followed by a space.'; var rx = /(?:[^\n.?;:.]|[\n?;:?.](?;\s))+[\n:;..;]+/g; console.log( s.match(rx) );