将 Unicode 中的结果传递给 Swift 中的字符串

Question

I am translating my String value to unicodeScalars with this down code, for example if I gave "A" as input I will get 65 as output, now that I know 65 is number of A , then I want give 65 to receive A again, but it gave e , I am sure I am mixing some topic together and also missing something, need some help for understanding why this is deferent and how can I use "\u{?????}" for returning my String, thanks

let string: String = "A"
let UInt32Value: UInt32 = string.unicodeScalars[string.startIndex].value
print(UInt32Value) // 65


let newString = "\u{65}"
print(newString) // e

ps: I know that there is official way of using unicodescalar to get the String back, but I am interested to "\u{?????}"

Answer 1

try to convert as follows

let ans =  String(UnicodeScalar(UInt8(65)))
print(ans)

I think the problem is, you are converting (A) string -> unicodescalar -> uint

and have to convert (65) uint -> unicodescalar -> string to get the original value

Answer 2

The \u{...} escape sequence uses hex:

Special characters can be included in string literals of both the single-line and multiline forms using the following escape sequences:

• [...]
• Unicode scalar ( \u{n} ), where n is a hexadecimal number that has one to eight digits

From the language reference .

So you need

"\u{41}"