C 程序查找最大和最小元素时出错

Question

Can anyone help me spot the error in my program in finding the minimum and maximum element in a agiven array. I know that it is a simple error but I cannot figure it out.

#include <stdio.h>
    # define SIZE 10
    int main()
    {
            int min;
            int max;
            int i; //counter variable
            int arr[SIZE] = {2,4,5,7,8,100,4,1};
    
            //check min and max of given array
            min = arr[0];
            max = arr[0];
            for(i =0; i< SIZE;i++)
            {
                    if(arr[i]<min)
                    {
                            min = arr[i];
                    }
                    if(arr[i]>max)
                    {
                            max = arr[i];
                    }
            }
            printf("minimum is %d\n",min);
            printf("maximum is %d\n",max);
    
            return 0;
    }

Answer 1

You are defining an array of 10 elements and initializing only 8 of them. The remaining two array elements are zero-initialized . That is why your min var is set to 0 .

Alternatively define a macro to have a value of 8:

#define SIZE 8

or define an array as following:

int arr[] = {2, 4, 5, 7, 8, 100, 4, 1};

and obtain the array size through the following expression where needed:

sizeof(arr) / sizeof(arr[0])

With arrays of unknown size , the compiler deduces the array size based on the number of initializers, which in our case is 8 and it is the same as if we had written: int arr[8] .