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Linq 根据最近的总和查询 select 记录

[英]Linq query to select records based on most recent sum

I'm writing a method that selects customer records based on a group by with the most recent purchase total equal (passed to the method).我正在编写一种方法,该方法根据最近的购买总额相等(传递给该方法)的组来选择客户记录。 I did some search and nothing showed up that helps me to achieve the desired output.我做了一些搜索,但没有任何结果可以帮助我实现所需的 output。

 customerList.GroupBy(x=> x.CustomerID },
                      (key, result) =>
                      {
                       var orderedList = result.OrderByDescending(c => c.Date).ToList();

                      return new Customer
                      {
                          CustomerID = orderedList.First().CustomerID,
                          PurchaseID = orderedList.First().PurchaseID,
                          Price = orderedList.First().Price,
                     };
                   });
CUSTOMERID客户ID PURCHACEID采购编号 PRICE价格 DATE日期
1 1 11 11 235 235 01-03-2021 01-03-2021
1 1 12 12 230 230 01-03-2021 01-03-2021
1 1 14 14 235 235 05-04-2021 05-04-2021
1 1 15 15 535 535 06-04-2021 06-04-2021
1 1 16 16 230 230 07-04-2021 07-04-2021

If I'm looking for most recent total purchase price of 1000, I should get如果我正在寻找最近 1000 的总购买价格,我应该得到

CUSTOMERID客户ID PURCHACEID采购编号 PRICE价格 DATE日期
1 1 14 14 235 235 05-04-2021 05-04-2021
1 1 15 15 535 535 06-04-2021 06-04-2021
1 1 16 16 230 230 07-04-2021 07-04-2021

You probably need to produce a separate list with the cumulative sums .您可能需要使用累积和生成一个单独的列表。 You can then use TakeWhile to take items until some condition is reached然后,您可以使用TakeWhile来获取项目,直到达到某些条件

var list = new[] { 1, 2, 3, 4, 5 };
var sum = 0;
var cummulativeSums = list.Select(v => sum += v).ToList();
var result= list.TakeWhile((_, index) => cummulativeSums[index] < 7).ToList();
// 1, 2, 3

Or you could do it all in one go by creating intermediate pair of values.或者您可以通过创建中间值对在一个 go 中完成所有操作。

var list = new[] { 1, 2, 3, 4, 5 };
var sum = 0;
var result = list.Select(value => (sum += value, value))
    .TakeWhile(pair => pair.Item1 < 7)
    .Select(pair => pair.value)
    .ToList();

         

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