[英]Convert Postgresql into HiveSql
How do I convert below mentioned postgresql query into HiveSql如何将下面提到的 postgresql 查询转换为 HiveSql
SELECT
COUNT(user_id) Total_profiles,
COUNT(user_id) FITLER (WHERE profile_date BETWEEN '2020-01-01' AND '2020-03-31') as Q1_profile,
COUNT(user_id) FITLER (WHERE profile_date BETWEEN '2020-04-01' AND '2020-06-30') as Q2_profile,
COUNT(user_id) FITLER (WHERE profile_date BETWEEN '2020-07-01' AND '2020-09-30') as Q3_profile,
COUNT(user_id) FITLER (WHERE profile_date BETWEEN '2020-010-01' AND '2020-12-31') as Q4_profile
FROM
customer_profiles
WHERE
profile_date BETWEEN '2020-01-01' AND '2020-12-31'
Use CASE expressions like this:像这样使用 CASE 表达式:
SELECT
COUNT(user_id) Total_profiles,
COUNT(case when profile_date BETWEEN '2020-01-01' AND '2020-03-31' then user_id else null end) as Q1_profile,
COUNT(case when profile_date BETWEEN '2020-04-01' AND '2020-06-30' then user_id else null end) as Q2_profile,
COUNT(case when profile_date BETWEEN '2020-07-01' AND '2020-09-30' then user_id else null end) as Q3_profile,
COUNT(case when profile_date BETWEEN '2020-10-01' AND '2020-12-31' then user_id else null end) as Q4_profile
FROM
customer_profiles
WHERE
profile_date BETWEEN '2020-01-01' AND '2020-12-31'
Also in Hive version >= 1.3 you can use quarter
function:同样在 Hive 版本 >= 1.3 中,您可以使用quarter
function:
SELECT
COUNT(user_id) Total_profiles,
COUNT(case when quarter(profile_date)=1 then user_id else null end) as Q1_profile,
COUNT(case when quarter(profile_date)=2 then user_id else null end) as Q2_profile,
COUNT(case when quarter(profile_date)=3 then user_id else null end) as Q3_profile,
COUNT(case when quarter(profile_date)=4 then user_id else null end) as Q4_profile
FROM
customer_profiles
WHERE
profile_date BETWEEN '2020-01-01' AND '2020-12-31'
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