[英]Check if a given key in an associative array has a value
Assume I have an array like this:假设我有一个这样的数组:
$Data = array(
'User1' => array(
'FirstName' => 'John',
'MiddleName' => '',
'LastName' => 'Doe',
),
'User2' => array(
'FirstName' => 'John',
'MiddleName' => '',
'LastName' => 'Smith',
),
);
I want to check, if no dataset in the array has a value for MiddleName.我想检查,如果数组中没有数据集具有 MiddleName 的值。
I wanted to ask, if there is a built-in function/one-liner in PHP to do something like this:我想问一下,PHP 中是否有内置函数/单线可以执行以下操作:
IF( AllEmpty($Data["MiddleName"]) ) { Do something }
Thank you very much!非常感谢!
If you insist on a one-liner, it can be done like this:如果您坚持使用单线,则可以这样做:
if (!array_filter(array_column($Data, 'MiddleName'))) {
echo 'Nothing here';
}
How it works:这个怎么运作:
array_column
obtains all the values of 'MiddleName' as an array ['', '']
array_column
获取 'MiddleName' 的所有值作为数组['', '']
array_filter
(without any additional parameters) returns an array with any falsey values removed, resulting in an empty array as empty strings are considered falsey array_filter
(不带任何附加参数)返回一个删除了任何虚假值的数组,导致一个空数组,因为空字符串被认为是虚假的array_filter(array_column($Data, 'MiddleName')) === []
if we want to be explicit or even as empty(array_filter...
)由于空数组本身是错误的,因此我们否定表达式以便满足条件array_filter(array_column($Data, 'MiddleName')) === []
如果我们想要显式或即使是empty(array_filter...
)using loop to check each element使用循环检查每个元素
foreach($Data as $x => $value) {
if(!middlename_check($value['MiddleName'])){
echo 'MiddleName is empty!';
}
// Do something
}
function middlename_check($middlename) {
if($middlename != '') {
return true;
}
return false;
}
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