从 XPATH 中的所有元素中检索属性值

Question

I have an XML File which has a root called "Node", and the rest of the tags are called Variables, Shapes etc.

<Node Name="X0578">
    <Dynamo Name="grpConditionDispAlarm" Description="" Class="Group" Category="Shape">
        <ContainedObjects>
            <Shape Name="grpSettings18" Description="" Class="Group" Category="Shape">
                <ContainedObjects>
                    <Shape Name="Text279" Description="" Class="Text" Category="Shape">
                    </Shape>
                </ContainedObjects>
            </Shape>
        </ContainedObjects>
    </Dynamo>
</Node>

When I try to parse the XML and get a list of Shapes with their attribute "Name" and their XPATH (which i am getting it from tree.getpath(shapes) )

I get a list

/Node/Dynamo[1]/ContainedObjects/Shape[1]
/Node/Dynamo[1]/ContainedObjects/Shape[1]/ContainedObjects/Shape

My files contain multiple instances of tag called Dynamo . I need to get a list of all those Dynamos with each shape that's inside.

for dynamo in source_tree.iterfind(".//Dynamo"):
    dynamo_tree = etree.ElementTree(dynamo)
    object_list = dynamo_tree.findall(".//Shape")
    for each_obj in object_list:
        ### Extract Info
        Obj_Name = each_obj.attrib["Name"]
        obj_Path = source_tree.getpath(each_obj)
        ## Uses Pandas DF to save the data 

Output as below:

Object Name	XPATH
grpSettings18	/Node/Dynamo[1]/ContainedObjects/Shape[1]
Text279	/Node/Dynamo[1]/ContainedObjects/Shape[1]/ContainedObjects/Shape

Now, technically for us, the XPATH doesn't make much sense.
But every Shape, Dynamo has an Attribute Called "Name".
So we want to replace that Dynamo[1], Shape[1], Shape in that XPATH with their respective attribute value "Name".

def resolvepath(docroot, shape_path):
    lstPath = shape_path.split('/')
    lstPath.pop(0)
    strxpath = "/"
    resolvepath = "/"

    for elem in lstPath:
        if not elem == 'ContainedObjects':
            strxpath = strxpath + '/' + elem
            resolvepath = resolvepath + '/' + docroot.xpath(strxpath)[0].attrib['Name']
        elif elem == 'ContainedObjects':
            strxpath = strxpath + '/' + 'ContainedObjects'
    return resolvepath

I used the above logic to iterate through Objects XPath and create a new string resolvepath which then replaces Dynamo[1] , Shape[1] with their attrib. Name .

Output as Below:

Object Name	XPATH	Node Name	Dynamo Name	Resolved Path
grpSettings18	/Node/Dynamo[1]/ContainedObjects/Shape[1]	X0579	grpConditionDispAlarm	//X0579/grpConditionDispAlarm/grpSettings18
Text279	/Node/Dynamo[1]/ContainedObjects/Shape[1]/ContainedObjects/Shape	X0579	grpConditionDispAlarm	//X0579/grpConditionDispAlarm/grpSettings18/Text279

Now my main concern is that def resolvepath takes a lot of time when we consider that depth of shapes may go till 7-8 level.

Answer 1

Is it possible to resolve the XPATH and get a path according to their Element & Attribute Value?

You mean something like

/*[@Name="RandomNodeName"]/ContainedObjects/*[@Name="RandomName32"]/ContainedObjects/*[@Name="RandomName33"]/ContainedObjects/*[@Name="RandomName34"]

?