计算从 for 循环返回的所有值的总值

Question

I have a for loop which is going through a list of IPS, connecting to a device, finding a specific value, calculating how many times this value is present, and then printing the number of times it is found.

I achieve this by using the len() function.

See below code:

for line in IPS:
    try:
        IPS = line.strip()
        device = ConnectHandler(device_type=platform, ip=IPS, username=username,
                                password=password)
        connectedregex = len(re.findall(r"connected", output))
        notconnectregex = len(re.findall(r"notconnect", output))
        errdisable = len(re.findall(r"errdisable", output))
        print(connectedregex, notconnectregex, errdisable)

The above code will output as an example:

1, 1, 1
2, 2, 2

What I would like to do, is at the end, add all these values together and just print the total, so the above would actually print as: (for each value 1+2 = 3)

3, 3, 3

I have tried using sum() , and taking my print statement outside the for loop, however this does not work.

Answer 1

You can do it fairly easily by using the built-in sum() function in conjunction with itertools.zip_longest() .

I can't run the code in your question of course, but here's some sample code that should give you the idea of how to do something similar:

from itertools import zip_longest


IPS = [(1, 2, 3), (2, 3, 4), (3, 4, 5)]

totals = []
for line in IPS:
    connected, notconnect, errdisable = line
    print(connected, notconnect, errdisable)
    totals = [sum(values) for values in
                zip_longest(totals, (connected, notconnect, errdisable),
                            fillvalue=0)]

print()
print('totals:', totals)

Output:

1 2 3
2 3 4
3 4 5

totals: [6, 9, 12]