[英]Some numbers are skipped in counting number of values greater and less than certain values in a list
I'm having problems with counting the number of values greater than start
(initially 0) and less than end
(initially 10) certain values in a list.我在计算列表中大于
start
(最初为 0)和小于end
(最初为 10)某些值的值的数量时遇到问题。
The list contains 12 500 float numbers from the range 0 - 110. I want to count how many numbers out of the list are in the range 0-10, then 10-20, 20-30, (...), 100-110该列表包含 0-110 范围内的 12 500 个浮点数。我想计算列表中有多少数字在 0-10 范围内,然后是 10-20、20-30、(...)、100- 110
I have implemented a for loop with a list comprehension inside like that:我已经实现了一个带有列表理解的 for 循环,如下所示:
all_nums = [] # contains 12_500 float numbers
nums_counted = []
start = 0
end = 10
for x in range(11):
count = len([x for x in to_int if start < x < end])
nums_counted.append(count)
start = start + 10
end = end + 10
The problem is len(all_nums) = 12500
and sum(nums_counted) = 12492
, which should be equal to 12 500 as well.问题是
len(all_nums) = 12500
和sum(nums_counted) = 12492
,它们也应该等于 12 500。
I do not know what am I doing wrong and where those 8 numbers disappear我不知道我做错了什么以及那 8 个数字在哪里消失了
You can just do int division by 10您可以将 int 除以 10
> from collections import Counter
>
> l = [0.0, 0.1, 6.1, 11.4, 19.2, 20.9, 40.1]
>
> d = Counter()
>
> for val in l:
> binn = val//10
> d[binn] += 1
>
> print(l)
> print(d.items())
[0.0, 0.1, 6.1, 11.4, 19.2, 20.9, 40.1]
dict_items([(0.0, 3), (1.0, 2), (2.0, 1), (4.0, 1)])
In this case 0.0 --> 0-10 range which has 3 count在这种情况下 0.0 --> 0-10 范围内有 3 个计数
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